Issolvi sin(-5pidiv6)

$$\sin ( -5 \pi \div 6 )$$

Evalwa

$$-\frac{1}{2}=-0.5$$

Passi tas-Soluzzjonijiet

Uża \sin(x+y)=\sin(x)\cos(y)+\sin(y)\cos(x) fejn x=\frac{\pi }{2} u y=\frac{\pi }{3} biex tikseb ir-riżultat.

$$\sin(\frac{\pi }{2}+\frac{\pi }{3})=\sin(\frac{\pi }{2})\cos(\frac{\pi }{3})+\sin(\frac{\pi }{3})\cos(\frac{\pi }{2})$$

Ikseb il-valur ta’ \sin(\frac{\pi }{2}) mit-tabella tal-valuri trigonometriċi.

$$1\cos(\frac{\pi }{3})+\sin(\frac{\pi }{3})\cos(\frac{\pi }{2})$$

Ikseb il-valur ta’ \cos(\frac{\pi }{3}) mit-tabella tal-valuri trigonometriċi.

$$1\times \frac{1}{2}+\sin(\frac{\pi }{3})\cos(\frac{\pi }{2})$$

Ikseb il-valur ta’ \sin(\frac{\pi }{3}) mit-tabella tal-valuri trigonometriċi.

$$1\times \frac{1}{2}+\frac{\sqrt{3}}{2}\cos(\frac{\pi }{2})$$

Ikseb il-valur ta’ \cos(\frac{\pi }{2}) mit-tabella tal-valuri trigonometriċi.

$$1\times \frac{1}{2}+\frac{\sqrt{3}}{2}\times 0$$

Agħmel il-kalkoli.

$$\frac{1}{2}$$

Fattur

$$-\frac{1}{2} = -0.5$$