Issolvi quady=Acos(x-B)

$$\quad y = A \cos ( x - B )$$

Solvi għal A

$$\left\{\begin{matrix}A=\frac{y}{\cos(x-B)}\text{, }&\nexists n_{1}\in \mathrm{Z}\text{ : }x=\pi n_{1}+B+\frac{\pi }{2}\\A\in \mathrm{R}\text{, }&y=0\text{ and }\exists n_{1}\in \mathrm{Z}\text{ : }x=\pi n_{1}+B+\frac{\pi }{2}\end{matrix}\right.$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Ibdel in-naħat sabiex it-termini varjabbli kollha jkunu fuq in-naħa tax-xellug.

$$A\cos(x-B)=y$$

L-ekwazzjoni hija f'forma standard.

$$\cos(x-B)A=y$$

Iddividi ż-żewġ naħat b'\cos(x-B).

$$\frac{\cos(x-B)A}{\cos(x-B)}=\frac{y}{\cos(x-B)}$$

Meta tiddividi b'\cos(x-B) titneħħa l-multiplikazzjoni b'\cos(x-B).

$$A=\frac{y}{\cos(x-B)}$$