Issolvi {l}{f(x)=-x^2+3x+5}{x=-3/5}

$$\left. \begin{array} { l } { f ( x ) = - x ^ { 2 } + 3 x + 5 } \\ { x = - \frac { 3 } { 5 } } \end{array} \right.$$

Solvi għal f, x

$$x=-\frac{3}{5}=-0.6$$

$$f = -\frac{71}{15} = -4\frac{11}{15} \approx -4.733333333$$

Passi tas-Soluzzjonijiet

Ikkunsidra l-ewwel ekwazzjoni. Inserixxi l-valuri magħrufa tal-varjabbli fl-ekwazzjoni.

$$f\left(-\frac{3}{5}\right)=-\left(-\frac{3}{5}\right)^{2}+3\left(-\frac{3}{5}\right)+5$$

Ikkalkula -\frac{3}{5} bil-power ta' 2 u tikseb \frac{9}{25}.

$$f\left(-\frac{3}{5}\right)=-\frac{9}{25}+3\left(-\frac{3}{5}\right)+5$$

Immultiplika 3 u -\frac{3}{5} biex tikseb -\frac{9}{5}.

$$f\left(-\frac{3}{5}\right)=-\frac{9}{25}-\frac{9}{5}+5$$

Naqqas \frac{9}{5} minn -\frac{9}{25} biex tikseb -\frac{54}{25}.

$$f\left(-\frac{3}{5}\right)=-\frac{54}{25}+5$$

Żid -\frac{54}{25} u 5 biex tikseb \frac{71}{25}.

$$f\left(-\frac{3}{5}\right)=\frac{71}{25}$$

Immultiplika ż-żewġ naħat b'-\frac{5}{3}, ir-reċiproku ta' -\frac{3}{5}.

$$f=\frac{71}{25}\left(-\frac{5}{3}\right)$$

Immultiplika \frac{71}{25} u -\frac{5}{3} biex tikseb -\frac{71}{15}.

$$f=-\frac{71}{15}$$

Is-sistema issa solvuta.

$$f=-\frac{71}{15} x=-\frac{3}{5}$$