Issolvi {l}{a_{n}=42-4{(n-1)}}{n=1}{a=2}{b=a}{c=b}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { a_{n} = 42 - 4 {(n - 1)} }\\ { n = 1 }\\ { a = 2 }\\ { b = a }\\ { c = b }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Solvi għal a_n, n, a, b, c, d

$$d=2$$

Passi tas-Soluzzjonijiet

Ikkunsidra l-ewwel ekwazzjoni. Inserixxi l-valuri magħrufa tal-varjabbli fl-ekwazzjoni.

$$a_{n}=42-4\left(1-1\right)$$

Naqqas 1 minn 1 biex tikseb 0.

$$a_{n}=42-4\times 0$$

Immultiplika -4 u 0 biex tikseb 0.

$$a_{n}=42+0$$

Żid 42 u 0 biex tikseb 42.

$$a_{n}=42$$

Is-sistema issa solvuta.

$$a_{n}=42 n=1 a=2 b=2 c=2 d=2$$