Issolvi {l}{4x-1=0}{y={(4x-1)}{(x+5)}-{(4x-1)}{(2x+3)}}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { 4 x - 1 = 0 }\\ { y = {(4 x - 1)} {(x + 5)} - {(4 x - 1)} {(2 x + 3)} }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solvi għal x, y, z

$$z=0$$

Passi tas-Soluzzjonijiet

Ikkunsidra l-ewwel ekwazzjoni. Żid 1 maż-żewġ naħat. Xi ħaġa plus żero jirriżulta f'dan in-numru stess.

$$4x=1$$

Iddividi ż-żewġ naħat b'4.

$$x=\frac{1}{4}$$

Ikkunsidra t-tieni ekwazzjoni. Inserixxi l-valuri magħrufa tal-varjabbli fl-ekwazzjoni.

$$y=\left(4\times \frac{1}{4}-1\right)\left(\frac{1}{4}+5\right)-\left(4\times \frac{1}{4}-1\right)\left(2\times \frac{1}{4}+3\right)$$

Immultiplika 4 u \frac{1}{4} biex tikseb 1.

$$y=\left(1-1\right)\left(\frac{1}{4}+5\right)-\left(4\times \frac{1}{4}-1\right)\left(2\times \frac{1}{4}+3\right)$$

Naqqas 1 minn 1 biex tikseb 0.

$$y=0\left(\frac{1}{4}+5\right)-\left(4\times \frac{1}{4}-1\right)\left(2\times \frac{1}{4}+3\right)$$

Żid \frac{1}{4} u 5 biex tikseb \frac{21}{4}.

$$y=0\times \frac{21}{4}-\left(4\times \frac{1}{4}-1\right)\left(2\times \frac{1}{4}+3\right)$$

Immultiplika 0 u \frac{21}{4} biex tikseb 0.

$$y=0-\left(4\times \frac{1}{4}-1\right)\left(2\times \frac{1}{4}+3\right)$$

Immultiplika 4 u \frac{1}{4} biex tikseb 1.

$$y=0-\left(1-1\right)\left(2\times \frac{1}{4}+3\right)$$

Naqqas 1 minn 1 biex tikseb 0.

$$y=0-0\left(2\times \frac{1}{4}+3\right)$$

Immultiplika 2 u \frac{1}{4} biex tikseb \frac{1}{2}.

$$y=0-0\left(\frac{1}{2}+3\right)$$

Żid \frac{1}{2} u 3 biex tikseb \frac{7}{2}.

$$y=0-0\times \frac{7}{2}$$

Immultiplika 0 u \frac{7}{2} biex tikseb 0.

$$y=0-0$$

Jekk tnaqqas 0 minnu nnifsu jibqa' 0.

$$y=0$$

Ikkunsidra t-tielet ekwazzjoni. Inserixxi l-valuri magħrufa tal-varjabbli fl-ekwazzjoni.

$$z=0$$

Is-sistema issa solvuta.

$$x=\frac{1}{4} y=0 z=0$$