Issolvi {l}{4{(3m+2)}-5{(6m-1)}=2{(m-8)}-6{(7m-4)}}{n=4m}{text{Solvefor}otext{where}}{o=n}

$$\left. \begin{array} { l } { 4 {(3 m + 2)} - 5 {(6 m - 1)} = 2 {(m - 8)} - 6 {(7 m - 4)} }\\ { n = 4 m }\\ { \text{Solve for } o \text{ where} } \\ { o = n } \end{array} \right.$$

Solvi għal m, n, o

$$o=-\frac{10}{11}\approx -0.909090909$$

Passi tas-Soluzzjonijiet

Ikkunsidra l-ewwel ekwazzjoni. Uża l-propjetà distributtiva biex timmultiplika 4 b'3m+2.

$$12m+8-5\left(6m-1\right)=2\left(m-8\right)-6\left(7m-4\right)$$

Uża l-propjetà distributtiva biex timmultiplika -5 b'6m-1.

$$12m+8-30m+5=2\left(m-8\right)-6\left(7m-4\right)$$

Ikkombina 12m u -30m biex tikseb -18m.

$$-18m+8+5=2\left(m-8\right)-6\left(7m-4\right)$$

Żid 8 u 5 biex tikseb 13.

$$-18m+13=2\left(m-8\right)-6\left(7m-4\right)$$

Uża l-propjetà distributtiva biex timmultiplika 2 b'm-8.

$$-18m+13=2m-16-6\left(7m-4\right)$$

Uża l-propjetà distributtiva biex timmultiplika -6 b'7m-4.

$$-18m+13=2m-16-42m+24$$

Ikkombina 2m u -42m biex tikseb -40m.

$$-18m+13=-40m-16+24$$

Żid -16 u 24 biex tikseb 8.

$$-18m+13=-40m+8$$

Żid 40m maż-żewġ naħat.

$$-18m+13+40m=8$$

Ikkombina -18m u 40m biex tikseb 22m.

$$22m+13=8$$

Naqqas 13 miż-żewġ naħat.

$$22m=8-13$$

Naqqas 13 minn 8 biex tikseb -5.

$$22m=-5$$

Iddividi ż-żewġ naħat b'22.

$$m=-\frac{5}{22}$$

Ikkunsidra t-tieni ekwazzjoni. Inserixxi l-valuri magħrufa tal-varjabbli fl-ekwazzjoni.

$$n=4\left(-\frac{5}{22}\right)$$

Immultiplika 4 u -\frac{5}{22} biex tikseb -\frac{10}{11}.

$$n=-\frac{10}{11}$$

Ikkunsidra t-tielet ekwazzjoni. Inserixxi l-valuri magħrufa tal-varjabbli fl-ekwazzjoni.

$$o=-\frac{10}{11}$$

Is-sistema issa solvuta.

$$m=-\frac{5}{22} n=-\frac{10}{11} o=-\frac{10}{11}$$