Issolvi {l}{4*{(x+3)}=6*{(x-2)}}{y=3}{z=y}{a=z}{b=a}{text{Solvefor}ctext{where}}{c=b}

$$\left. \begin{array} { l } { 4 \cdot {(x + 3)} = 6 \cdot {(x - 2)} }\\ { y = 3 }\\ { z = y }\\ { a = z }\\ { b = a }\\ { \text{Solve for } c \text{ where} } \\ { c = b } \end{array} \right.$$

Solvi għal x, y, z, a, b, c

$$c=3$$

Passi tas-Soluzzjonijiet

Ikkunsidra l-ewwel ekwazzjoni. Uża l-propjetà distributtiva biex timmultiplika 4 b'x+3.

$$4x+12=6\left(x-2\right)$$

Uża l-propjetà distributtiva biex timmultiplika 6 b'x-2.

$$4x+12=6x-12$$

Naqqas 6x miż-żewġ naħat.

$$4x+12-6x=-12$$

Ikkombina 4x u -6x biex tikseb -2x.

$$-2x+12=-12$$

Naqqas 12 miż-żewġ naħat.

$$-2x=-12-12$$

Naqqas 12 minn -12 biex tikseb -24.

$$-2x=-24$$

Iddividi ż-żewġ naħat b'-2.

$$x=\frac{-24}{-2}$$

Iddividi -24 b'-2 biex tikseb12.

$$x=12$$

Is-sistema issa solvuta.

$$x=12 y=3 z=3 a=3 b=3 c=3$$