Issolvi {l}{28-{(m+4*2)}=15093}{n=31}{o=n}{p=o}{q=p}{r=q}{s=r}{t=s}{text{Solvefor}utext{where}}{u=t}

$$\left. \begin{array} { l } { 28 - {(m + 4 \cdot 2)} = 15093 }\\ { n = 31 }\\ { o = n }\\ { p = o }\\ { q = p }\\ { r = q }\\ { s = r }\\ { t = s }\\ { \text{Solve for } u \text{ where} } \\ { u = t } \end{array} \right.$$

Solvi għal m, n, o, p, q, r, s, t, u

$$u=31$$

Passi tas-Soluzzjonijiet

Ikkunsidra l-ewwel ekwazzjoni. Immultiplika 4 u 2 biex tikseb 8.

$$28-\left(m+8\right)=15093$$

Biex issib l-oppost ta' m+8, sib l-oppost ta' kull terminu.

$$28-m-8=15093$$

Naqqas 8 minn 28 biex tikseb 20.

$$20-m=15093$$

Naqqas 20 miż-żewġ naħat.

$$-m=15093-20$$

Naqqas 20 minn 15093 biex tikseb 15073.

$$-m=15073$$

Iddividi ż-żewġ naħat b'-1.

$$m=-15073$$

Is-sistema issa solvuta.

$$m=-15073 n=31 o=31 p=31 q=31 r=31 s=31 t=31 u=31$$