Issolvi {l}{2{(0*251*4*472.578+0.7486y)}=321.487}{y=0.1449x+0.2739*472.578+0.5812y}{z=x-0}{a=z}{b=a}{text{Solvefor}ctext{where}}{c=b}

$$\left. \begin{array} { l } { 2 {(0 \cdot 251 \cdot 4 \cdot 472.578 + 0.7486 y)} = 321.487 }\\ { y = 0.1449 x + 0.2739 \cdot 472.578 + 0.5812 y }\\ { z = x - 0 }\\ { a = z }\\ { b = a }\\ { \text{Solve for } c \text{ where} } \\ { c = b } \end{array} \right.$$

Solvi għal y, x, z, a, b, c

$$c = -\frac{35212789393}{129133500} = -272\frac{88477393}{129133500} \approx -272.6851622$$

Passi tas-Soluzzjonijiet

Ikkunsidra l-ewwel ekwazzjoni. Iddividi ż-żewġ naħat b'2.

$$0\times 251\times 4\times 472.578+0.7486y=\frac{321.487}{2}$$

Espandi \frac{321.487}{2} billi timmultiplika kemm in-numeratur kif ukoll id-denominatur b'1000.

$$0\times 251\times 4\times 472.578+0.7486y=\frac{321487}{2000}$$

Immultiplika 0 u 251 biex tikseb 0.

$$0\times 4\times 472.578+0.7486y=\frac{321487}{2000}$$

Immultiplika 0 u 4 biex tikseb 0.

$$0\times 472.578+0.7486y=\frac{321487}{2000}$$

Immultiplika 0 u 472.578 biex tikseb 0.

$$0+0.7486y=\frac{321487}{2000}$$

Xi ħaġa plus żero jirriżulta f'dan in-numru stess.

$$0.7486y=\frac{321487}{2000}$$

Iddividi ż-żewġ naħat b'0.7486.

$$y=\frac{\frac{321487}{2000}}{0.7486}$$

Esprimi \frac{\frac{321487}{2000}}{0.7486} bħala frazzjoni waħda.

$$y=\frac{321487}{2000\times 0.7486}$$

Immultiplika 2000 u 0.7486 biex tikseb 1497.2.

$$y=\frac{321487}{1497.2}$$

Espandi \frac{321487}{1497.2} billi timmultiplika kemm in-numeratur kif ukoll id-denominatur b'10.

$$y=\frac{3214870}{14972}$$

Naqqas il-frazzjoni \frac{3214870}{14972} għat-termini l-aktar baxxi billi testratta u tikkanċella barra 2.

$$y=\frac{1607435}{7486}$$

Ikkunsidra t-tieni ekwazzjoni. Inserixxi l-valuri magħrufa tal-varjabbli fl-ekwazzjoni.

$$\frac{1607435}{7486}=0.1449x+0.2739\times 472.578+0.5812\times \frac{1607435}{7486}$$

Immultiplika 0.2739 u 472.578 biex tikseb 129.4391142.

$$\frac{1607435}{7486}=0.1449x+129.4391142+0.5812\times \frac{1607435}{7486}$$

Immultiplika 0.5812 u \frac{1607435}{7486} biex tikseb \frac{467120611}{3743000}.

$$\frac{1607435}{7486}=0.1449x+129.4391142+\frac{467120611}{3743000}$$

Żid 129.4391142 u \frac{467120611}{3743000} biex tikseb \frac{4758056077253}{18715000000}.

$$\frac{1607435}{7486}=0.1449x+\frac{4758056077253}{18715000000}$$

Ibdel in-naħat sabiex it-termini varjabbli kollha jkunu fuq in-naħa tax-xellug.

$$0.1449x+\frac{4758056077253}{18715000000}=\frac{1607435}{7486}$$

Naqqas \frac{4758056077253}{18715000000} miż-żewġ naħat.

$$0.1449x=\frac{1607435}{7486}-\frac{4758056077253}{18715000000}$$

Naqqas \frac{4758056077253}{18715000000} minn \frac{1607435}{7486} biex tikseb -\frac{739468577253}{18715000000}.

$$0.1449x=-\frac{739468577253}{18715000000}$$

Iddividi ż-żewġ naħat b'0.1449.

$$x=\frac{-\frac{739468577253}{18715000000}}{0.1449}$$

Esprimi \frac{-\frac{739468577253}{18715000000}}{0.1449} bħala frazzjoni waħda.

$$x=\frac{-739468577253}{18715000000\times 0.1449}$$

Immultiplika 18715000000 u 0.1449 biex tikseb 2711803500.

$$x=\frac{-739468577253}{2711803500}$$

Naqqas il-frazzjoni \frac{-739468577253}{2711803500} għat-termini l-aktar baxxi billi testratta u tikkanċella barra 21.

$$x=-\frac{35212789393}{129133500}$$

Ikkunsidra t-tielet ekwazzjoni. Inserixxi l-valuri magħrufa tal-varjabbli fl-ekwazzjoni.

$$z=-\frac{35212789393}{129133500}-0$$

Naqqas 0 minn -\frac{35212789393}{129133500} biex tikseb -\frac{35212789393}{129133500}.

$$z=-\frac{35212789393}{129133500}$$

Ikkunsidra r-raba' ekwazzjoni. Inserixxi l-valuri magħrufa tal-varjabbli fl-ekwazzjoni.

$$a=-\frac{35212789393}{129133500}$$

Ikkunsidra l-ħames ekwazzjoni. Inserixxi l-valuri magħrufa tal-varjabbli fl-ekwazzjoni.

$$b=-\frac{35212789393}{129133500}$$

Ikkunsidra l-ekwazzjoni (6). Inserixxi l-valuri magħrufa tal-varjabbli fl-ekwazzjoni.

$$c=-\frac{35212789393}{129133500}$$

Is-sistema issa solvuta.

$$y=\frac{1607435}{7486} x=-\frac{35212789393}{129133500} z=-\frac{35212789393}{129133500} a=-\frac{35212789393}{129133500} b=-\frac{35212789393}{129133500} c=-\frac{35212789393}{129133500}$$