Issolvi {l}{15-3{(x+4)}=12-2{(x+3)}}{y=1}{z=y}{a=z}{text{Solvefor}btext{where}}{b=a}

$$\left. \begin{array} { l } { 15 - 3 {(x + 4)} = 12 - 2 {(x + 3)} }\\ { y = 1 }\\ { z = y }\\ { a = z }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.$$

Solvi għal x, y, z, a, b

$$b=1$$

Passi tas-Soluzzjonijiet

Ikkunsidra l-ewwel ekwazzjoni. Uża l-propjetà distributtiva biex timmultiplika -3 b'x+4.

$$15-3x-12=12-2\left(x+3\right)$$

Naqqas 12 minn 15 biex tikseb 3.

$$3-3x=12-2\left(x+3\right)$$

Uża l-propjetà distributtiva biex timmultiplika -2 b'x+3.

$$3-3x=12-2x-6$$

Naqqas 6 minn 12 biex tikseb 6.

$$3-3x=6-2x$$

Żid 2x maż-żewġ naħat.

$$3-3x+2x=6$$

Ikkombina -3x u 2x biex tikseb -x.

$$3-x=6$$

Naqqas 3 miż-żewġ naħat.

$$-x=6-3$$

Naqqas 3 minn 6 biex tikseb 3.

$$-x=3$$

Iddividi ż-żewġ naħat b'-1.

$$x=-3$$

Is-sistema issa solvuta.

$$x=-3 y=1 z=1 a=1 b=1$$