Issolvi {l}{frac{3{(x+1)}}{2}+frac{5{(x+1)}}{3}=4}{y=2}{z=y}{a=z}{b=a}{text{Solvefor}ctext{where}}{c=b}

$$\left. \begin{array} { l } { \frac{3 {(x + 1)}}{2} + \frac{5 {(x + 1)}}{3} = 4 }\\ { y = 2 }\\ { z = y }\\ { a = z }\\ { b = a }\\ { \text{Solve for } c \text{ where} } \\ { c = b } \end{array} \right.$$

Solvi għal x, y, z, a, b, c

$$c=2$$

Passi tas-Soluzzjonijiet

Ikkunsidra l-ewwel ekwazzjoni. Immultiplika ż-żewġ naħat tal-ekwazzjoni b'6, l-inqas denominatur komuni ta' 2,3.

$$3\times 3\left(x+1\right)+2\times 5\left(x+1\right)=24$$

Immultiplika 3 u 3 biex tikseb 9.

$$9\left(x+1\right)+2\times 5\left(x+1\right)=24$$

Uża l-propjetà distributtiva biex timmultiplika 9 b'x+1.

$$9x+9+2\times 5\left(x+1\right)=24$$

Immultiplika 2 u 5 biex tikseb 10.

$$9x+9+10\left(x+1\right)=24$$

Uża l-propjetà distributtiva biex timmultiplika 10 b'x+1.

$$9x+9+10x+10=24$$

Ikkombina 9x u 10x biex tikseb 19x.

$$19x+9+10=24$$

Żid 9 u 10 biex tikseb 19.

$$19x+19=24$$

Naqqas 19 miż-żewġ naħat.

$$19x=24-19$$

Naqqas 19 minn 24 biex tikseb 5.

$$19x=5$$

Iddividi ż-żewġ naħat b'19.

$$x=\frac{5}{19}$$

Is-sistema issa solvuta.

$$x=\frac{5}{19} y=2 z=2 a=2 b=2 c=2$$