\left\{ \begin{array} { l } { x + y = 3 } \\ { x ^ { 2 } + y ^ { 3 } = 13 } \end{array} \right.
Solvi għal x, y
x=\frac{2\left(-\sqrt{19}\cos(\frac{\arccos(\frac{26\sqrt{19}}{361})}{3})+5\right)}{3}\approx 0.676595724\text{, }y=\frac{2\sqrt{19}\cos(\frac{\arccos(\frac{26\sqrt{19}}{361})}{3})-1}{3}\approx 2.323404276
x=\frac{\sqrt{19}\cos(\frac{\arccos(\frac{26\sqrt{19}}{361})}{3})+\sqrt{57}\sin(\frac{\arccos(\frac{26\sqrt{19}}{361})}{3})+10}{3}\approx 5.681330644\text{, }y=\frac{-\sqrt{19}\cos(\frac{\arccos(\frac{26\sqrt{19}}{361})}{3})-\sqrt{57}\sin(\frac{\arccos(\frac{26\sqrt{19}}{361})}{3})-1}{3}\approx -2.681330644
x=\frac{\sqrt{19}\cos(\frac{\arccos(\frac{26\sqrt{19}}{361})}{3})-\sqrt{57}\sin(\frac{\arccos(\frac{26\sqrt{19}}{361})}{3})+10}{3}\approx 3.642073632\text{, }y=\frac{\sqrt{57}\sin(\frac{\arccos(\frac{26\sqrt{19}}{361})}{3})-\sqrt{19}\cos(\frac{\arccos(\frac{26\sqrt{19}}{361})}{3})-1}{3}\approx -0.642073632
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