Issolvi ∫ (8/7-1/2)^2+(3/4-3/7)^2

$$\int ( \frac { 8 } { 7 } - \frac { 1 } { 2 } ) ^ { 2 } + ( \frac { 3 } { 4 } - \frac { 3 } { 7 } ) ^ { 2 }$$

Evalwa

$$\frac{405x}{784}+С$$

Passi tas-Soluzzjonijiet

Naqqas \frac{1}{2} minn \frac{8}{7} biex tikseb \frac{9}{14}.

$$\int \left(\frac{9}{14}\right)^{2}+\left(\frac{3}{4}-\frac{3}{7}\right)^{2}\mathrm{d}x$$

Ikkalkula \frac{9}{14} bil-power ta' 2 u tikseb \frac{81}{196}.

$$\int \frac{81}{196}+\left(\frac{3}{4}-\frac{3}{7}\right)^{2}\mathrm{d}x$$

Naqqas \frac{3}{7} minn \frac{3}{4} biex tikseb \frac{9}{28}.

$$\int \frac{81}{196}+\left(\frac{9}{28}\right)^{2}\mathrm{d}x$$

Ikkalkula \frac{9}{28} bil-power ta' 2 u tikseb \frac{81}{784}.

$$\int \frac{81}{196}+\frac{81}{784}\mathrm{d}x$$

Żid \frac{81}{196} u \frac{81}{784} biex tikseb \frac{405}{784}.

$$\int \frac{405}{784}\mathrm{d}x$$

Sib l-integru ta' \frac{405}{784} billi tuża t-tabella tar-regola tal-integrali komuni \int a\mathrm{d}x=ax.

$$\frac{405x}{784}$$

Jekk F\left(x\right) huwa antiderivattiv ta' f\left(x\right), allura s-sett tal-antiderivati kollha ta' f\left(x\right) jingħata minn F\left(x\right)+C. Għalhekk, żid il-kostanti ta' integrazzjoni C\in \mathrm{R} mar-riżultat.

$$\frac{405x}{784}+С$$

Iddifferenzja w.r.t. x

$$\frac{405}{784} = 0.5165816326530612$$