Issolvi 1/4(x+1)(x-1)(x-1)(x+1)+x^2=1/4(x^2+1)(x^2+1)

$$\frac{ 1 }{ 4 } (x+1)(x-1)(x-1)(x+1)+ { x }^{ 2 } = \frac{ 1 }{ 4 } ( { x }^{ 2 } +1)( { x }^{ 2 } +1)$$

Solvi għal x (complex solution)

$$x\in \mathrm{C}$$

Passi tas-Soluzzjonijiet

Immultiplika x+1 u x+1 biex tikseb \left(x+1\right)^{2}.

$$\frac{1}{4}\left(x+1\right)^{2}\left(x-1\right)\left(x-1\right)+x^{2}=\frac{1}{4}\left(x^{2}+1\right)\left(x^{2}+1\right)$$

Immultiplika x-1 u x-1 biex tikseb \left(x-1\right)^{2}.

$$\frac{1}{4}\left(x+1\right)^{2}\left(x-1\right)^{2}+x^{2}=\frac{1}{4}\left(x^{2}+1\right)\left(x^{2}+1\right)$$

Immultiplika x^{2}+1 u x^{2}+1 biex tikseb \left(x^{2}+1\right)^{2}.

$$\frac{1}{4}\left(x+1\right)^{2}\left(x-1\right)^{2}+x^{2}=\frac{1}{4}\left(x^{2}+1\right)^{2}$$

Uża teorema binomjali \left(a+b\right)^{2}=a^{2}+2ab+b^{2} biex tespandi \left(x+1\right)^{2}.

$$\frac{1}{4}\left(x^{2}+2x+1\right)\left(x-1\right)^{2}+x^{2}=\frac{1}{4}\left(x^{2}+1\right)^{2}$$

Uża teorema binomjali \left(a-b\right)^{2}=a^{2}-2ab+b^{2} biex tespandi \left(x-1\right)^{2}.

$$\frac{1}{4}\left(x^{2}+2x+1\right)\left(x^{2}-2x+1\right)+x^{2}=\frac{1}{4}\left(x^{2}+1\right)^{2}$$

Uża l-propjetà distributtiva biex timmultiplika \frac{1}{4} b'x^{2}+2x+1.

$$\left(\frac{1}{4}x^{2}+\frac{1}{2}x+\frac{1}{4}\right)\left(x^{2}-2x+1\right)+x^{2}=\frac{1}{4}\left(x^{2}+1\right)^{2}$$

Uża l-propjetà distributtiva biex timmultiplika \frac{1}{4}x^{2}+\frac{1}{2}x+\frac{1}{4} b'x^{2}-2x+1 u kkombina termini simili.

$$\frac{1}{4}x^{4}-\frac{1}{2}x^{2}+\frac{1}{4}+x^{2}=\frac{1}{4}\left(x^{2}+1\right)^{2}$$

Ikkombina -\frac{1}{2}x^{2} u x^{2} biex tikseb \frac{1}{2}x^{2}.

$$\frac{1}{4}x^{4}+\frac{1}{2}x^{2}+\frac{1}{4}=\frac{1}{4}\left(x^{2}+1\right)^{2}$$

Uża teorema binomjali \left(a+b\right)^{2}=a^{2}+2ab+b^{2} biex tespandi \left(x^{2}+1\right)^{2}.

$$\frac{1}{4}x^{4}+\frac{1}{2}x^{2}+\frac{1}{4}=\frac{1}{4}\left(\left(x^{2}\right)^{2}+2x^{2}+1\right)$$

Biex tgħolli l-qawwa ta' numru għal qawwa oħra, immultiplika l-esponenti. Immultiplika 2 u 2 biex tikseb 4.

$$\frac{1}{4}x^{4}+\frac{1}{2}x^{2}+\frac{1}{4}=\frac{1}{4}\left(x^{4}+2x^{2}+1\right)$$

Uża l-propjetà distributtiva biex timmultiplika \frac{1}{4} b'x^{4}+2x^{2}+1.

$$\frac{1}{4}x^{4}+\frac{1}{2}x^{2}+\frac{1}{4}=\frac{1}{4}x^{4}+\frac{1}{2}x^{2}+\frac{1}{4}$$

Naqqas \frac{1}{4}x^{4} miż-żewġ naħat.

$$\frac{1}{4}x^{4}+\frac{1}{2}x^{2}+\frac{1}{4}-\frac{1}{4}x^{4}=\frac{1}{2}x^{2}+\frac{1}{4}$$

Ikkombina \frac{1}{4}x^{4} u -\frac{1}{4}x^{4} biex tikseb 0.

$$\frac{1}{2}x^{2}+\frac{1}{4}=\frac{1}{2}x^{2}+\frac{1}{4}$$

Naqqas \frac{1}{2}x^{2} miż-żewġ naħat.

$$\frac{1}{2}x^{2}+\frac{1}{4}-\frac{1}{2}x^{2}=\frac{1}{4}$$

Ikkombina \frac{1}{2}x^{2} u -\frac{1}{2}x^{2} biex tikseb 0.

$$\frac{1}{4}=\frac{1}{4}$$

Qabbel \frac{1}{4} u \frac{1}{4}.

$$\text{true}$$

Din hija vera għal kwalunkwe x.

$$x\in \mathrm{C}$$

Solvi għal x

$$x\in \mathrm{R}$$

Passi tas-Soluzzjonijiet

Immultiplika x+1 u x+1 biex tikseb \left(x+1\right)^{2}.

$$\frac{1}{4}\left(x+1\right)^{2}\left(x-1\right)\left(x-1\right)+x^{2}=\frac{1}{4}\left(x^{2}+1\right)\left(x^{2}+1\right)$$

Immultiplika x-1 u x-1 biex tikseb \left(x-1\right)^{2}.

$$\frac{1}{4}\left(x+1\right)^{2}\left(x-1\right)^{2}+x^{2}=\frac{1}{4}\left(x^{2}+1\right)\left(x^{2}+1\right)$$

Immultiplika x^{2}+1 u x^{2}+1 biex tikseb \left(x^{2}+1\right)^{2}.

$$\frac{1}{4}\left(x+1\right)^{2}\left(x-1\right)^{2}+x^{2}=\frac{1}{4}\left(x^{2}+1\right)^{2}$$

Uża teorema binomjali \left(a+b\right)^{2}=a^{2}+2ab+b^{2} biex tespandi \left(x+1\right)^{2}.

$$\frac{1}{4}\left(x^{2}+2x+1\right)\left(x-1\right)^{2}+x^{2}=\frac{1}{4}\left(x^{2}+1\right)^{2}$$

Uża teorema binomjali \left(a-b\right)^{2}=a^{2}-2ab+b^{2} biex tespandi \left(x-1\right)^{2}.

$$\frac{1}{4}\left(x^{2}+2x+1\right)\left(x^{2}-2x+1\right)+x^{2}=\frac{1}{4}\left(x^{2}+1\right)^{2}$$

Uża l-propjetà distributtiva biex timmultiplika \frac{1}{4} b'x^{2}+2x+1.

$$\left(\frac{1}{4}x^{2}+\frac{1}{2}x+\frac{1}{4}\right)\left(x^{2}-2x+1\right)+x^{2}=\frac{1}{4}\left(x^{2}+1\right)^{2}$$

Uża l-propjetà distributtiva biex timmultiplika \frac{1}{4}x^{2}+\frac{1}{2}x+\frac{1}{4} b'x^{2}-2x+1 u kkombina termini simili.

$$\frac{1}{4}x^{4}-\frac{1}{2}x^{2}+\frac{1}{4}+x^{2}=\frac{1}{4}\left(x^{2}+1\right)^{2}$$

Ikkombina -\frac{1}{2}x^{2} u x^{2} biex tikseb \frac{1}{2}x^{2}.

$$\frac{1}{4}x^{4}+\frac{1}{2}x^{2}+\frac{1}{4}=\frac{1}{4}\left(x^{2}+1\right)^{2}$$

Uża teorema binomjali \left(a+b\right)^{2}=a^{2}+2ab+b^{2} biex tespandi \left(x^{2}+1\right)^{2}.

$$\frac{1}{4}x^{4}+\frac{1}{2}x^{2}+\frac{1}{4}=\frac{1}{4}\left(\left(x^{2}\right)^{2}+2x^{2}+1\right)$$

Biex tgħolli l-qawwa ta' numru għal qawwa oħra, immultiplika l-esponenti. Immultiplika 2 u 2 biex tikseb 4.

$$\frac{1}{4}x^{4}+\frac{1}{2}x^{2}+\frac{1}{4}=\frac{1}{4}\left(x^{4}+2x^{2}+1\right)$$

Uża l-propjetà distributtiva biex timmultiplika \frac{1}{4} b'x^{4}+2x^{2}+1.

$$\frac{1}{4}x^{4}+\frac{1}{2}x^{2}+\frac{1}{4}=\frac{1}{4}x^{4}+\frac{1}{2}x^{2}+\frac{1}{4}$$

Naqqas \frac{1}{4}x^{4} miż-żewġ naħat.

$$\frac{1}{4}x^{4}+\frac{1}{2}x^{2}+\frac{1}{4}-\frac{1}{4}x^{4}=\frac{1}{2}x^{2}+\frac{1}{4}$$

Ikkombina \frac{1}{4}x^{4} u -\frac{1}{4}x^{4} biex tikseb 0.

$$\frac{1}{2}x^{2}+\frac{1}{4}=\frac{1}{2}x^{2}+\frac{1}{4}$$

Naqqas \frac{1}{2}x^{2} miż-żewġ naħat.

$$\frac{1}{2}x^{2}+\frac{1}{4}-\frac{1}{2}x^{2}=\frac{1}{4}$$

Ikkombina \frac{1}{2}x^{2} u -\frac{1}{2}x^{2} biex tikseb 0.

$$\frac{1}{4}=\frac{1}{4}$$

Qabbel \frac{1}{4} u \frac{1}{4}.

$$\text{true}$$

Din hija vera għal kwalunkwe x.

$$x\in \mathrm{R}$$