Issolvi frac{sqrt{3}+sqrt{6}+sqrt{2}+1+2sqrt{8}}{2}

$$\frac{ \sqrt{ 3 } + \sqrt{ 6 } + \sqrt{ 2 } +1+2 \sqrt{ 8 } }{ 2 }$$

Evalwa

$$\frac{\sqrt{3}+\sqrt{6}+5\sqrt{2}+1}{2}\approx 6.126304181$$

Passi tas-Soluzzjonijiet

Iffattura 8=2^{2}\times 2. Erġa' ikteb l-għerq kwadrat tal-prodott \sqrt{2^{2}\times 2} bħala l-prodott tal-għeruq kwadrati \sqrt{2^{2}}\sqrt{2}. Ħu l-għerq kwadrat ta' 2^{2}.

$$\frac{\sqrt{3}+\sqrt{6}+\sqrt{2}+1+2\times 2\sqrt{2}}{2}$$

Immultiplika 2 u 2 biex tikseb 4.

$$\frac{\sqrt{3}+\sqrt{6}+\sqrt{2}+1+4\sqrt{2}}{2}$$

Ikkombina \sqrt{2} u 4\sqrt{2} biex tikseb 5\sqrt{2}.

$$\frac{\sqrt{3}+\sqrt{6}+5\sqrt{2}+1}{2}$$