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\frac{\left(\sqrt{14}+2\right)\left(1+\sqrt{7}\right)}{\left(1-\sqrt{7}\right)\left(1+\sqrt{7}\right)}
Irrazzjonalizza d-denominatur tal-\frac{\sqrt{14}+2}{1-\sqrt{7}} billi timmultiplika in-numeratur u d-denominatur mill-1+\sqrt{7}.
\frac{\left(\sqrt{14}+2\right)\left(1+\sqrt{7}\right)}{1^{2}-\left(\sqrt{7}\right)^{2}}
Ikkunsidra li \left(1-\sqrt{7}\right)\left(1+\sqrt{7}\right). Il-multiplikazzjoni tista' tiġi ttrasformata fid-differenza tal-kwadrati li jużaw ir-regola: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{\left(\sqrt{14}+2\right)\left(1+\sqrt{7}\right)}{1-7}
Ikkwadra 1. Ikkwadra \sqrt{7}.
\frac{\left(\sqrt{14}+2\right)\left(1+\sqrt{7}\right)}{-6}
Naqqas 7 minn 1 biex tikseb -6.
\frac{\sqrt{14}+\sqrt{14}\sqrt{7}+2+2\sqrt{7}}{-6}
Applika l-propjetà distributtiva billi timmultiplika kull terminu ta' \sqrt{14}+2 b'kull terminu ta' 1+\sqrt{7}.
\frac{\sqrt{14}+\sqrt{7}\sqrt{2}\sqrt{7}+2+2\sqrt{7}}{-6}
Iffattura 14=7\times 2. Erġa' ikteb l-għerq kwadrat tal-prodott \sqrt{7\times 2} bħala l-prodott tal-għeruq kwadrati \sqrt{7}\sqrt{2}.
\frac{\sqrt{14}+7\sqrt{2}+2+2\sqrt{7}}{-6}
Immultiplika \sqrt{7} u \sqrt{7} biex tikseb 7.
\frac{-\sqrt{14}-7\sqrt{2}-2-2\sqrt{7}}{6}
Immultiplika kemm in-numeratur u kif ukoll id-denominatur b’-1.