Issolvi x+4/x+3-x-3/x+4/frac{14{x^2+7x+12}}

$$\frac{ \frac{ x+4 }{ x+3 } - \frac{ x-3 }{ x+4 } }{ \frac{ 14 }{ { x }^{ 2 } +7x+12 } }$$

Evalwa

$$\frac{4x}{7}+\frac{25}{14}$$

Passi Qosra tas-Soluzzjonijiet

Biex iżżid jew tnaqqas l-espressjonijiet, espandihom biex id-denominaturi tagħhom ikunu l-istess. L-inqas multiplu komuni ta' x+3 u x+4 huwa \left(x+3\right)\left(x+4\right). Immultiplika \frac{x+4}{x+3} b'\frac{x+4}{x+4}. Immultiplika \frac{x-3}{x+4} b'\frac{x+3}{x+3}.

$$\frac{\frac{\left(x+4\right)\left(x+4\right)}{\left(x+3\right)\left(x+4\right)}-\frac{\left(x-3\right)\left(x+3\right)}{\left(x+3\right)\left(x+4\right)}}{\frac{14}{x^{2}+7x+12}}$$

Billi \frac{\left(x+4\right)\left(x+4\right)}{\left(x+3\right)\left(x+4\right)} u \frac{\left(x-3\right)\left(x+3\right)}{\left(x+3\right)\left(x+4\right)} għandhom l-istess denominatur, naqqashom billi tnaqqas in-numeraturi tagħhom.

$$\frac{\frac{\left(x+4\right)\left(x+4\right)-\left(x-3\right)\left(x+3\right)}{\left(x+3\right)\left(x+4\right)}}{\frac{14}{x^{2}+7x+12}}$$

Agħmel il-multiplikazzjonijiet fi \left(x+4\right)\left(x+4\right)-\left(x-3\right)\left(x+3\right).

$$\frac{\frac{x^{2}+4x+4x+16-x^{2}-3x+3x+9}{\left(x+3\right)\left(x+4\right)}}{\frac{14}{x^{2}+7x+12}}$$

Ikkombina termini simili f'x^{2}+4x+4x+16-x^{2}-3x+3x+9.

$$\frac{\frac{8x+25}{\left(x+3\right)\left(x+4\right)}}{\frac{14}{x^{2}+7x+12}}$$

Iddividi \frac{8x+25}{\left(x+3\right)\left(x+4\right)} b'\frac{14}{x^{2}+7x+12} billi timmultiplika \frac{8x+25}{\left(x+3\right)\left(x+4\right)} bir-reċiproku ta' \frac{14}{x^{2}+7x+12}.

$$\frac{\left(8x+25\right)\left(x^{2}+7x+12\right)}{\left(x+3\right)\left(x+4\right)\times 14}$$

Iffattura l-espressjonijiet li mhumiex diġà fatturati.

$$\frac{\left(x+3\right)\left(x+4\right)\left(8x+25\right)}{14\left(x+3\right)\left(x+4\right)}$$

Annulla \left(x+3\right)\left(x+4\right) fin-numeratur u d-denominatur.

$$\frac{8x+25}{14}$$

Espandi

$$\frac{4x}{7}+\frac{25}{14}$$

Passi Qosra tas-Soluzzjonijiet

Biex iżżid jew tnaqqas l-espressjonijiet, espandihom biex id-denominaturi tagħhom ikunu l-istess. L-inqas multiplu komuni ta' x+3 u x+4 huwa \left(x+3\right)\left(x+4\right). Immultiplika \frac{x+4}{x+3} b'\frac{x+4}{x+4}. Immultiplika \frac{x-3}{x+4} b'\frac{x+3}{x+3}.

$$\frac{\frac{\left(x+4\right)\left(x+4\right)}{\left(x+3\right)\left(x+4\right)}-\frac{\left(x-3\right)\left(x+3\right)}{\left(x+3\right)\left(x+4\right)}}{\frac{14}{x^{2}+7x+12}}$$

Billi \frac{\left(x+4\right)\left(x+4\right)}{\left(x+3\right)\left(x+4\right)} u \frac{\left(x-3\right)\left(x+3\right)}{\left(x+3\right)\left(x+4\right)} għandhom l-istess denominatur, naqqashom billi tnaqqas in-numeraturi tagħhom.

$$\frac{\frac{\left(x+4\right)\left(x+4\right)-\left(x-3\right)\left(x+3\right)}{\left(x+3\right)\left(x+4\right)}}{\frac{14}{x^{2}+7x+12}}$$

Agħmel il-multiplikazzjonijiet fi \left(x+4\right)\left(x+4\right)-\left(x-3\right)\left(x+3\right).

$$\frac{\frac{x^{2}+4x+4x+16-x^{2}-3x+3x+9}{\left(x+3\right)\left(x+4\right)}}{\frac{14}{x^{2}+7x+12}}$$

Ikkombina termini simili f'x^{2}+4x+4x+16-x^{2}-3x+3x+9.

$$\frac{\frac{8x+25}{\left(x+3\right)\left(x+4\right)}}{\frac{14}{x^{2}+7x+12}}$$

Iddividi \frac{8x+25}{\left(x+3\right)\left(x+4\right)} b'\frac{14}{x^{2}+7x+12} billi timmultiplika \frac{8x+25}{\left(x+3\right)\left(x+4\right)} bir-reċiproku ta' \frac{14}{x^{2}+7x+12}.

$$\frac{\left(8x+25\right)\left(x^{2}+7x+12\right)}{\left(x+3\right)\left(x+4\right)\times 14}$$

Iffattura l-espressjonijiet li mhumiex diġà fatturati.

$$\frac{\left(x+3\right)\left(x+4\right)\left(8x+25\right)}{14\left(x+3\right)\left(x+4\right)}$$

Annulla \left(x+3\right)\left(x+4\right) fin-numeratur u d-denominatur.

$$\frac{8x+25}{14}$$