Issolvi z-5/z^2-81-6-z/81-z^2 | Microsoft Math Solver

Evalwa

Espandi

Kwizz

Polynomial

5 problemi simili għal:

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https://socratic.org/questions/how-can-i-simplify-f-16-256g-4h-4-1-4

Sehem

Ikkupjat fuq il-klibbord

\frac{z-5}{\left(z-9\right)\left(z+9\right)}-\frac{6-z}{\left(z-9\right)\left(-z-9\right)}

Iffattura z^{2}-81. Iffattura 81-z^{2}.

\frac{z-5}{\left(z-9\right)\left(z+9\right)}-\frac{-\left(6-z\right)}{\left(z-9\right)\left(z+9\right)}

Biex iżżid jew tnaqqas l-espressjonijiet, espandihom biex id-denominaturi tagħhom ikunu l-istess. L-inqas multiplu komuni ta' \left(z-9\right)\left(z+9\right) u \left(z-9\right)\left(-z-9\right) huwa \left(z-9\right)\left(z+9\right). Immultiplika \frac{6-z}{\left(z-9\right)\left(-z-9\right)} b'\frac{-1}{-1}.

\frac{z-5-\left(-\left(6-z\right)\right)}{\left(z-9\right)\left(z+9\right)}

Billi \frac{z-5}{\left(z-9\right)\left(z+9\right)} u \frac{-\left(6-z\right)}{\left(z-9\right)\left(z+9\right)} għandhom l-istess denominatur, naqqashom billi tnaqqas in-numeraturi tagħhom.

\frac{z-5+6-z}{\left(z-9\right)\left(z+9\right)}

Agħmel il-multiplikazzjonijiet fi z-5-\left(-\left(6-z\right)\right).

\frac{1}{\left(z-9\right)\left(z+9\right)}

Ikkombina termini simili f'z-5+6-z.

\frac{1}{z^{2}-81}

Espandi \left(z-9\right)\left(z+9\right).