Issolvi b/8=frac{sqrt{100-x^2}}{40/3-x}

$$\frac { b } { 8 } = \frac { \sqrt { 100 - x ^ { 2 } } } { \frac { 40 } { 3 } - x }$$

Solvi għal b

$$b=\frac{24\sqrt{100-x^{2}}}{40-3x}$$

$$|x|\leq 10$$

Passi biex Issolvi l-Ekwazzjoni Lineari

L-ekwazzjoni hija f'forma standard.

$$\frac{1}{8}b=\frac{\sqrt{100-x^{2}}}{\frac{40}{3}-x}$$

Immultiplika ż-żewġ naħat b'8.

$$\frac{\frac{1}{8}b}{\frac{1}{8}}=\frac{3\sqrt{100-x^{2}}}{\frac{1}{8}\left(40-3x\right)}$$

Meta tiddividi b'\frac{1}{8} titneħħa l-multiplikazzjoni b'\frac{1}{8}.

$$b=\frac{3\sqrt{100-x^{2}}}{\frac{1}{8}\left(40-3x\right)}$$

Iddividi \frac{3\sqrt{100-x^{2}}}{40-3x} b'\frac{1}{8} billi timmultiplika \frac{3\sqrt{100-x^{2}}}{40-3x} bir-reċiproku ta' \frac{1}{8}.

$$b=\frac{24\sqrt{100-x^{2}}}{40-3x}$$

Solvi għal x

$$x=-\frac{40\left(-b^{2}+2\sqrt{576-7b^{2}}\right)}{3\left(b^{2}+64\right)}$$

$$x=\frac{40\left(b^{2}+2\sqrt{576-7b^{2}}\right)}{3\left(b^{2}+64\right)}\text{, }b\geq 0\text{ and }b\leq \frac{24\sqrt{7}}{7}$$