Issolvi a+1/a^2-a-a-1/a^2+a-1/a^2-1

$$\frac { a + 1 } { a ^ { 2 } - a } - \frac { a - 1 } { a ^ { 2 } + a } - \frac { 1 } { a ^ { 2 } - 1 }$$

Evalwa

$$\frac{3}{a^{2}-1}$$

Passi Qosra tas-Soluzzjonijiet

Iffattura a^{2}-a. Iffattura a^{2}+a.

$$\frac{a+1}{a\left(a-1\right)}-\frac{a-1}{a\left(a+1\right)}-\frac{1}{a^{2}-1}$$

Biex iżżid jew tnaqqas l-espressjonijiet, espandihom biex id-denominaturi tagħhom ikunu l-istess. L-inqas multiplu komuni ta' a\left(a-1\right) u a\left(a+1\right) huwa a\left(a-1\right)\left(a+1\right). Immultiplika \frac{a+1}{a\left(a-1\right)} b'\frac{a+1}{a+1}. Immultiplika \frac{a-1}{a\left(a+1\right)} b'\frac{a-1}{a-1}.

$$\frac{\left(a+1\right)\left(a+1\right)}{a\left(a-1\right)\left(a+1\right)}-\frac{\left(a-1\right)\left(a-1\right)}{a\left(a-1\right)\left(a+1\right)}-\frac{1}{a^{2}-1}$$

Billi \frac{\left(a+1\right)\left(a+1\right)}{a\left(a-1\right)\left(a+1\right)} u \frac{\left(a-1\right)\left(a-1\right)}{a\left(a-1\right)\left(a+1\right)} għandhom l-istess denominatur, naqqashom billi tnaqqas in-numeraturi tagħhom.

$$\frac{\left(a+1\right)\left(a+1\right)-\left(a-1\right)\left(a-1\right)}{a\left(a-1\right)\left(a+1\right)}-\frac{1}{a^{2}-1}$$

Agħmel il-multiplikazzjonijiet fi \left(a+1\right)\left(a+1\right)-\left(a-1\right)\left(a-1\right).

$$\frac{a^{2}+a+a+1-a^{2}+a+a-1}{a\left(a-1\right)\left(a+1\right)}-\frac{1}{a^{2}-1}$$

Ikkombina termini simili f'a^{2}+a+a+1-a^{2}+a+a-1.

$$\frac{4a}{a\left(a-1\right)\left(a+1\right)}-\frac{1}{a^{2}-1}$$

Annulla a fin-numeratur u d-denominatur.

$$\frac{4}{\left(a-1\right)\left(a+1\right)}-\frac{1}{a^{2}-1}$$

Iffattura a^{2}-1.

$$\frac{4}{\left(a-1\right)\left(a+1\right)}-\frac{1}{\left(a-1\right)\left(a+1\right)}$$

Billi \frac{4}{\left(a-1\right)\left(a+1\right)} u \frac{1}{\left(a-1\right)\left(a+1\right)} għandhom l-istess denominatur, naqqashom billi tnaqqas in-numeraturi tagħhom. Naqqas 1 minn 4 biex tikseb 3.

$$\frac{3}{\left(a-1\right)\left(a+1\right)}$$

Espandi \left(a-1\right)\left(a+1\right).

$$\frac{3}{a^{2}-1}$$

Espandi

$$\frac{3}{a^{2}-1}$$

Passi Qosra tas-Soluzzjonijiet

Iffattura a^{2}-a. Iffattura a^{2}+a.

$$\frac{a+1}{a\left(a-1\right)}-\frac{a-1}{a\left(a+1\right)}-\frac{1}{a^{2}-1}$$

Biex iżżid jew tnaqqas l-espressjonijiet, espandihom biex id-denominaturi tagħhom ikunu l-istess. L-inqas multiplu komuni ta' a\left(a-1\right) u a\left(a+1\right) huwa a\left(a-1\right)\left(a+1\right). Immultiplika \frac{a+1}{a\left(a-1\right)} b'\frac{a+1}{a+1}. Immultiplika \frac{a-1}{a\left(a+1\right)} b'\frac{a-1}{a-1}.

$$\frac{\left(a+1\right)\left(a+1\right)}{a\left(a-1\right)\left(a+1\right)}-\frac{\left(a-1\right)\left(a-1\right)}{a\left(a-1\right)\left(a+1\right)}-\frac{1}{a^{2}-1}$$

Billi \frac{\left(a+1\right)\left(a+1\right)}{a\left(a-1\right)\left(a+1\right)} u \frac{\left(a-1\right)\left(a-1\right)}{a\left(a-1\right)\left(a+1\right)} għandhom l-istess denominatur, naqqashom billi tnaqqas in-numeraturi tagħhom.

$$\frac{\left(a+1\right)\left(a+1\right)-\left(a-1\right)\left(a-1\right)}{a\left(a-1\right)\left(a+1\right)}-\frac{1}{a^{2}-1}$$

Agħmel il-multiplikazzjonijiet fi \left(a+1\right)\left(a+1\right)-\left(a-1\right)\left(a-1\right).

$$\frac{a^{2}+a+a+1-a^{2}+a+a-1}{a\left(a-1\right)\left(a+1\right)}-\frac{1}{a^{2}-1}$$

Ikkombina termini simili f'a^{2}+a+a+1-a^{2}+a+a-1.

$$\frac{4a}{a\left(a-1\right)\left(a+1\right)}-\frac{1}{a^{2}-1}$$

Annulla a fin-numeratur u d-denominatur.

$$\frac{4}{\left(a-1\right)\left(a+1\right)}-\frac{1}{a^{2}-1}$$

Iffattura a^{2}-1.

$$\frac{4}{\left(a-1\right)\left(a+1\right)}-\frac{1}{\left(a-1\right)\left(a+1\right)}$$

Billi \frac{4}{\left(a-1\right)\left(a+1\right)} u \frac{1}{\left(a-1\right)\left(a+1\right)} għandhom l-istess denominatur, naqqashom billi tnaqqas in-numeraturi tagħhom. Naqqas 1 minn 4 biex tikseb 3.

$$\frac{3}{\left(a-1\right)\left(a+1\right)}$$

Espandi \left(a-1\right)\left(a+1\right).

$$\frac{3}{a^{2}-1}$$