Issolvi 12/sqrt{2}+sqrt{18}

$$\frac { 12 } { \sqrt { 2 } } + \sqrt { 18 }$$

Evalwa

$$9\sqrt{2}\approx 12.727922061$$

Passi tas-Soluzzjonijiet

Irrazzjonalizza d-denominatur tal-\frac{12}{\sqrt{2}} billi timmultiplika in-numeratur u d-denominatur mill-\sqrt{2}.

$$\frac{12\sqrt{2}}{\left(\sqrt{2}\right)^{2}}+\sqrt{18}$$

Il-kwadrat ta' \sqrt{2} huwa 2.

$$\frac{12\sqrt{2}}{2}+\sqrt{18}$$

Iddividi 12\sqrt{2} b'2 biex tikseb6\sqrt{2}.

$$6\sqrt{2}+\sqrt{18}$$

Iffattura 18=3^{2}\times 2. Erġa' ikteb l-għerq kwadrat tal-prodott \sqrt{3^{2}\times 2} bħala l-prodott tal-għeruq kwadrati \sqrt{3^{2}}\sqrt{2}. Ħu l-għerq kwadrat ta' 3^{2}.

$$6\sqrt{2}+3\sqrt{2}$$

Ikkombina 6\sqrt{2} u 3\sqrt{2} biex tikseb 9\sqrt{2}.

$$9\sqrt{2}$$