Issolvi 1/x+4-1/x+3=

$$\frac { 1 } { x + 4 } - \frac { 1 } { x + 3 } =$$

Evalwa

$$-\frac{1}{\left(x+3\right)\left(x+4\right)}$$

Passi Qosra tas-Soluzzjonijiet

Biex iżżid jew tnaqqas l-espressjonijiet, espandihom biex id-denominaturi tagħhom ikunu l-istess. L-inqas multiplu komuni ta' x+4 u x+3 huwa \left(x+3\right)\left(x+4\right). Immultiplika \frac{1}{x+4} b'\frac{x+3}{x+3}. Immultiplika \frac{1}{x+3} b'\frac{x+4}{x+4}.

$$\frac{x+3}{\left(x+3\right)\left(x+4\right)}-\frac{x+4}{\left(x+3\right)\left(x+4\right)}$$

Billi \frac{x+3}{\left(x+3\right)\left(x+4\right)} u \frac{x+4}{\left(x+3\right)\left(x+4\right)} għandhom l-istess denominatur, naqqashom billi tnaqqas in-numeraturi tagħhom.

$$\frac{x+3-\left(x+4\right)}{\left(x+3\right)\left(x+4\right)}$$

Agħmel il-multiplikazzjonijiet fi x+3-\left(x+4\right).

$$\frac{x+3-x-4}{\left(x+3\right)\left(x+4\right)}$$

Ikkombina termini simili f'x+3-x-4.

$$\frac{-1}{\left(x+3\right)\left(x+4\right)}$$

Espandi \left(x+3\right)\left(x+4\right).

$$\frac{-1}{x^{2}+7x+12}$$

Iddifferenzja w.r.t. x

$$\frac{2x+7}{\left(\left(x+3\right)\left(x+4\right)\right)^{2}}$$