Issolvi 1/2p-(p+2)^2-q/6p^2

$$\frac { 1 } { 2 p } - \frac { ( p + 2 ) ^ { 2 } - q } { 6 p ^ { 2 } }$$

Evalwa

$$\frac{-p^{2}-p+q-4}{6p^{2}}$$

Passi Qosra tas-Soluzzjonijiet

Biex iżżid jew tnaqqas l-espressjonijiet, espandihom biex id-denominaturi tagħhom ikunu l-istess. L-inqas multiplu komuni ta' 2p u 6p^{2} huwa 6p^{2}. Immultiplika \frac{1}{2p} b'\frac{3p}{3p}.

$$\frac{3p}{6p^{2}}-\frac{\left(p+2\right)^{2}-q}{6p^{2}}$$

Billi \frac{3p}{6p^{2}} u \frac{\left(p+2\right)^{2}-q}{6p^{2}} għandhom l-istess denominatur, naqqashom billi tnaqqas in-numeraturi tagħhom.

$$\frac{3p-\left(\left(p+2\right)^{2}-q\right)}{6p^{2}}$$

Agħmel il-multiplikazzjonijiet fi 3p-\left(\left(p+2\right)^{2}-q\right).

$$\frac{3p-p^{2}-4p-4+q}{6p^{2}}$$

Ikkombina termini simili f'3p-p^{2}-4p-4+q.

$$\frac{-p-p^{2}-4+q}{6p^{2}}$$

Espandi

$$\frac{-p^{2}-p+q-4}{6p^{2}}$$

Passi Qosra tas-Soluzzjonijiet

Biex iżżid jew tnaqqas l-espressjonijiet, espandihom biex id-denominaturi tagħhom ikunu l-istess. L-inqas multiplu komuni ta' 2p u 6p^{2} huwa 6p^{2}. Immultiplika \frac{1}{2p} b'\frac{3p}{3p}.

$$\frac{3p}{6p^{2}}-\frac{\left(p+2\right)^{2}-q}{6p^{2}}$$

Billi \frac{3p}{6p^{2}} u \frac{\left(p+2\right)^{2}-q}{6p^{2}} għandhom l-istess denominatur, naqqashom billi tnaqqas in-numeraturi tagħhom.

$$\frac{3p-\left(\left(p+2\right)^{2}-q\right)}{6p^{2}}$$

Agħmel il-multiplikazzjonijiet fi 3p-\left(\left(p+2\right)^{2}-q\right).

$$\frac{3p-p^{2}-4p-4+q}{6p^{2}}$$

Ikkombina termini simili f'3p-p^{2}-4p-4+q.

$$\frac{-p-p^{2}-4+q}{6p^{2}}$$