Issolvi 1/(x^2+3)+1/(x+4)=

$$\frac { 1 } { ( x ^ { 2 } + 3 ) } + \frac { 1 } { ( x + 4 ) } =$$

Evalwa

$$\frac{x^{2}+x+7}{\left(x+4\right)\left(x^{2}+3\right)}$$

Passi Qosra tas-Soluzzjonijiet

Biex iżżid jew tnaqqas l-espressjonijiet, espandihom biex id-denominaturi tagħhom ikunu l-istess. L-inqas multiplu komuni ta' x^{2}+3 u x+4 huwa \left(x+4\right)\left(x^{2}+3\right). Immultiplika \frac{1}{x^{2}+3} b'\frac{x+4}{x+4}. Immultiplika \frac{1}{x+4} b'\frac{x^{2}+3}{x^{2}+3}.

$$\frac{x+4}{\left(x+4\right)\left(x^{2}+3\right)}+\frac{x^{2}+3}{\left(x+4\right)\left(x^{2}+3\right)}$$

Billi \frac{x+4}{\left(x+4\right)\left(x^{2}+3\right)} u \frac{x^{2}+3}{\left(x+4\right)\left(x^{2}+3\right)} għandhom l-istess denominatur, żidhom billi żżid in-numeraturi tagħhom.

$$\frac{x+4+x^{2}+3}{\left(x+4\right)\left(x^{2}+3\right)}$$

Ikkombina termini simili f'x+4+x^{2}+3.

$$\frac{x+7+x^{2}}{\left(x+4\right)\left(x^{2}+3\right)}$$

Espandi \left(x+4\right)\left(x^{2}+3\right).

$$\frac{x+7+x^{2}}{x^{3}+4x^{2}+3x+12}$$

Iddifferenzja w.r.t. x

$$-\frac{x^{4}+2x^{3}+22x^{2}+32x+9}{\left(\left(x+4\right)\left(x^{2}+3\right)\right)^{2}}$$