Issolvi frac{sqrt{3}}{4}x(-3/2x+24)

$$\frac { \sqrt { 3 } } { 4 } x ( - \frac { 3 } { 2 } x + 24 )$$

Evalwa

$$\frac{3\sqrt{3}x\left(16-x\right)}{8}$$

Passi Qosra tas-Soluzzjonijiet

Esprimi \frac{\sqrt{3}}{4}x bħala frazzjoni waħda.

$$\frac{\sqrt{3}x}{4}\left(-\frac{3}{2}x+24\right)$$

Uża l-propjetà distributtiva biex timmultiplika \frac{\sqrt{3}x}{4} b'-\frac{3}{2}x+24.

$$\frac{\sqrt{3}x}{4}\left(-\frac{3}{2}\right)x+24\times \frac{\sqrt{3}x}{4}$$

Immultiplika \frac{\sqrt{3}x}{4} b'-\frac{3}{2} billi timmultiplika n-numeratur bin-numeratur u d-denominatur bid-denominatur.

$$\frac{-\sqrt{3}x\times 3}{4\times 2}x+24\times \frac{\sqrt{3}x}{4}$$

Esprimi \frac{-\sqrt{3}x\times 3}{4\times 2}x bħala frazzjoni waħda.

$$\frac{-\sqrt{3}x\times 3x}{4\times 2}+24\times \frac{\sqrt{3}x}{4}$$

Ikkanċella l-akbar fattur komuni 4 f'24 u 4.

$$\frac{-\sqrt{3}x\times 3x}{4\times 2}+6\sqrt{3}x$$

Biex iżżid jew tnaqqas l-espressjonijiet, espandihom biex id-denominaturi tagħhom ikunu l-istess. Immultiplika 6\sqrt{3}x b'\frac{4\times 2}{4\times 2}.

$$\frac{-\sqrt{3}x\times 3x}{4\times 2}+\frac{6\sqrt{3}x\times 4\times 2}{4\times 2}$$

Billi \frac{-\sqrt{3}x\times 3x}{4\times 2} u \frac{6\sqrt{3}x\times 4\times 2}{4\times 2} għandhom l-istess denominatur, żidhom billi żżid in-numeraturi tagħhom.

$$\frac{-\sqrt{3}x\times 3x+6\sqrt{3}x\times 4\times 2}{4\times 2}$$

Agħmel il-multiplikazzjonijiet fi -\sqrt{3}x\times 3x+6\sqrt{3}x\times 4\times 2.

$$\frac{-3\sqrt{3}x^{2}+48\sqrt{3}x}{4\times 2}$$

Espandi 4\times 2.

$$\frac{-3\sqrt{3}x^{2}+48\sqrt{3}x}{8}$$

Fattur

$$\frac{3\sqrt{3}x\left(16-x\right)}{8}$$