Issolvi cosA/1+sinA+1+sinA/cosA=2operatorname{sic}A

$$\frac { \cos A } { 1 + \sin A } + \frac { 1 + \sin A } { \cos A } = 2 \operatorname { sic } A$$

Solvi għal c

$$c=\frac{-i}{As\cos(A)}$$

$$s\neq 0\text{ and }\nexists n_{1}\in \mathrm{Z}\text{ : }A=\pi n_{1}+\frac{\pi }{2}\text{ and }A\neq 0$$

Passi biex Issolvi l-Ekwazzjoni Lineari

Immultiplika 2 u i biex tikseb 2i.

$$\frac{\cos(A)}{1+\sin(A)}+\frac{1+\sin(A)}{\cos(A)}=2iscA$$

Ibdel in-naħat sabiex it-termini varjabbli kollha jkunu fuq in-naħa tax-xellug.

$$2iscA=\frac{\cos(A)}{1+\sin(A)}+\frac{1+\sin(A)}{\cos(A)}$$

L-ekwazzjoni hija f'forma standard.

$$2iAsc=\frac{\cos(A)}{\sin(A)+1}+\frac{\sin(A)+1}{\cos(A)}$$

Iddividi ż-żewġ naħat b'2isA.

$$\frac{2iAsc}{2iAs}=\frac{2}{\cos(A)\times \left(2i\right)As}$$

Meta tiddividi b'2isA titneħħa l-multiplikazzjoni b'2isA.

$$c=\frac{2}{\cos(A)\times \left(2i\right)As}$$

Iddividi \frac{2}{\cos(A)} b'2isA.

$$c=\frac{-i}{As\cos(A)}$$