Issolvi frac{{(sqrt{169}-4)*(1+sqrt{25})}}{(sqrt{49}-1)}+sqrt{sqrt[3]{729}}

$$\frac { \{ ( \sqrt { 169 } - 4 ) \cdot ( 1 + \sqrt { 25 } ) \} } { ( \sqrt { 49 } - 1 ) } + \sqrt { \sqrt[ 3 ] { 729 } }$$

Evalwa

$$12$$

Passi tas-Soluzzjonijiet

Ikkalkula l-għerq kwadrat ta' 169 u ikseb 13.

$$\frac{\left(13-4\right)\left(1+\sqrt{25}\right)}{\sqrt{49}-1}+\sqrt{\sqrt[3]{729}}$$

Naqqas 4 minn 13 biex tikseb 9.

$$\frac{9\left(1+\sqrt{25}\right)}{\sqrt{49}-1}+\sqrt{\sqrt[3]{729}}$$

Ikkalkula l-għerq kwadrat ta' 25 u ikseb 5.

$$\frac{9\left(1+5\right)}{\sqrt{49}-1}+\sqrt{\sqrt[3]{729}}$$

Żid 1 u 5 biex tikseb 6.

$$\frac{9\times 6}{\sqrt{49}-1}+\sqrt{\sqrt[3]{729}}$$

Immultiplika 9 u 6 biex tikseb 54.

$$\frac{54}{\sqrt{49}-1}+\sqrt{\sqrt[3]{729}}$$

Ikkalkula l-għerq kwadrat ta' 49 u ikseb 7.

$$\frac{54}{7-1}+\sqrt{\sqrt[3]{729}}$$

Naqqas 1 minn 7 biex tikseb 6.

$$\frac{54}{6}+\sqrt{\sqrt[3]{729}}$$

Iddividi 54 b'6 biex tikseb9.

$$9+\sqrt{\sqrt[3]{729}}$$

Ikkalkola \sqrt[3]{729} u ikseb 9.

$$9+\sqrt{9}$$

Ikkalkula l-għerq kwadrat ta' 9 u ikseb 3.

$$9+3$$

Żid 9 u 3 biex tikseb 12.

$$12$$

Fattur

$$2^{2}\times 3$$