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\cos(\pi +\frac{\pi }{6})=\cos(\pi )\cos(\frac{\pi }{6})-\sin(\frac{\pi }{6})\sin(\pi )
Uża \cos(x+y)=\cos(x)\cos(y)-\sin(y)\sin(x) fejn x=\pi u y=\frac{\pi }{6} biex tikseb ir-riżultat.
-\cos(\frac{\pi }{6})-\sin(\frac{\pi }{6})\sin(\pi )
Ikseb il-valur ta’ \cos(\pi ) mit-tabella tal-valuri trigonometriċi.
-\frac{\sqrt{3}}{2}-\sin(\frac{\pi }{6})\sin(\pi )
Ikseb il-valur ta’ \cos(\frac{\pi }{6}) mit-tabella tal-valuri trigonometriċi.
-\frac{\sqrt{3}}{2}-\frac{1}{2}\sin(\pi )
Ikseb il-valur ta’ \sin(\frac{\pi }{6}) mit-tabella tal-valuri trigonometriċi.
-\frac{\sqrt{3}}{2}-\frac{1}{2}\times 0
Ikseb il-valur ta’ \sin(\pi ) mit-tabella tal-valuri trigonometriċi.
-\frac{\sqrt{3}}{2}
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