Issolvi =368quad[(3/28a^2b)(-7/4ab)-(-1/8a^3b)(+2b)]:(-1/4a^2b^2)

$$= 368 \quad [ ( \frac { 3 } { 28 } a ^ { 2 } b ) ( - \frac { 7 } { 4 } a b ) - ( - \frac { 1 } { 8 } a ^ { 3 } b ) ( + 2 b ) ] : ( - \frac { 1 } { 4 } a ^ { 2 } b ^ { 2 } )$$

Evalwa

$$-92a$$

Passi tas-Soluzzjonijiet

Biex timmultiplika l-qawwa tal-istess bażi, żid l-esponenti tagħhom. Żid 2 u 1 biex tikseb 3.

$$\frac{368\left(\frac{3}{28}a^{3}b\left(-\frac{7}{4}\right)b-\left(-\frac{1}{8}a^{3}b\times 2b\right)\right)}{-\frac{1}{4}a^{2}b^{2}}$$

Immultiplika b u b biex tikseb b^{2}.

$$\frac{368\left(\frac{3}{28}a^{3}b^{2}\left(-\frac{7}{4}\right)-\left(-\frac{1}{8}a^{3}b\times 2b\right)\right)}{-\frac{1}{4}a^{2}b^{2}}$$

Immultiplika b u b biex tikseb b^{2}.

$$\frac{368\left(\frac{3}{28}a^{3}b^{2}\left(-\frac{7}{4}\right)-\left(-\frac{1}{8}a^{3}b^{2}\times 2\right)\right)}{-\frac{1}{4}a^{2}b^{2}}$$

Immultiplika \frac{3}{28} u -\frac{7}{4} biex tikseb -\frac{3}{16}.

$$\frac{368\left(-\frac{3}{16}a^{3}b^{2}-\left(-\frac{1}{8}a^{3}b^{2}\times 2\right)\right)}{-\frac{1}{4}a^{2}b^{2}}$$

Immultiplika -\frac{1}{8} u 2 biex tikseb -\frac{1}{4}.

$$\frac{368\left(-\frac{3}{16}a^{3}b^{2}-\left(-\frac{1}{4}a^{3}b^{2}\right)\right)}{-\frac{1}{4}a^{2}b^{2}}$$

L-oppost ta' -\frac{1}{4}a^{3}b^{2} huwa \frac{1}{4}a^{3}b^{2}.

$$\frac{368\left(-\frac{3}{16}a^{3}b^{2}+\frac{1}{4}a^{3}b^{2}\right)}{-\frac{1}{4}a^{2}b^{2}}$$

Ikkombina -\frac{3}{16}a^{3}b^{2} u \frac{1}{4}a^{3}b^{2} biex tikseb \frac{1}{16}a^{3}b^{2}.

$$\frac{368\times \frac{1}{16}a^{3}b^{2}}{-\frac{1}{4}a^{2}b^{2}}$$

Immultiplika 368 u \frac{1}{16} biex tikseb 23.

$$\frac{23a^{3}b^{2}}{-\frac{1}{4}a^{2}b^{2}}$$

Annulla a^{2}b^{2} fin-numeratur u d-denominatur.

$$\frac{23a}{-\frac{1}{4}}$$

Iddividi 23a b'-\frac{1}{4} billi timmultiplika 23a bir-reċiproku ta' -\frac{1}{4}.

$$\frac{23a\times 4}{-1}$$

Immultiplika 23 u 4 biex tikseb 92.

$$\frac{92a}{-1}$$

Kwalunkwe ħaġa diviża b '-1 jagħtik oppost tiegħu.

$$-92a$$

Espandi

$$-92a$$

Passi tas-Soluzzjonijiet

Biex timmultiplika l-qawwa tal-istess bażi, żid l-esponenti tagħhom. Żid 2 u 1 biex tikseb 3.

$$\frac{368\left(\frac{3}{28}a^{3}b\left(-\frac{7}{4}\right)b-\left(-\frac{1}{8}a^{3}b\times 2b\right)\right)}{-\frac{1}{4}a^{2}b^{2}}$$

Immultiplika b u b biex tikseb b^{2}.

$$\frac{368\left(\frac{3}{28}a^{3}b^{2}\left(-\frac{7}{4}\right)-\left(-\frac{1}{8}a^{3}b\times 2b\right)\right)}{-\frac{1}{4}a^{2}b^{2}}$$

Immultiplika b u b biex tikseb b^{2}.

$$\frac{368\left(\frac{3}{28}a^{3}b^{2}\left(-\frac{7}{4}\right)-\left(-\frac{1}{8}a^{3}b^{2}\times 2\right)\right)}{-\frac{1}{4}a^{2}b^{2}}$$

Immultiplika \frac{3}{28} u -\frac{7}{4} biex tikseb -\frac{3}{16}.

$$\frac{368\left(-\frac{3}{16}a^{3}b^{2}-\left(-\frac{1}{8}a^{3}b^{2}\times 2\right)\right)}{-\frac{1}{4}a^{2}b^{2}}$$

Immultiplika -\frac{1}{8} u 2 biex tikseb -\frac{1}{4}.

$$\frac{368\left(-\frac{3}{16}a^{3}b^{2}-\left(-\frac{1}{4}a^{3}b^{2}\right)\right)}{-\frac{1}{4}a^{2}b^{2}}$$

L-oppost ta' -\frac{1}{4}a^{3}b^{2} huwa \frac{1}{4}a^{3}b^{2}.

$$\frac{368\left(-\frac{3}{16}a^{3}b^{2}+\frac{1}{4}a^{3}b^{2}\right)}{-\frac{1}{4}a^{2}b^{2}}$$

Ikkombina -\frac{3}{16}a^{3}b^{2} u \frac{1}{4}a^{3}b^{2} biex tikseb \frac{1}{16}a^{3}b^{2}.

$$\frac{368\times \frac{1}{16}a^{3}b^{2}}{-\frac{1}{4}a^{2}b^{2}}$$

Immultiplika 368 u \frac{1}{16} biex tikseb 23.

$$\frac{23a^{3}b^{2}}{-\frac{1}{4}a^{2}b^{2}}$$

Annulla a^{2}b^{2} fin-numeratur u d-denominatur.

$$\frac{23a}{-\frac{1}{4}}$$

Iddividi 23a b'-\frac{1}{4} billi timmultiplika 23a bir-reċiproku ta' -\frac{1}{4}.

$$\frac{23a\times 4}{-1}$$

Immultiplika 23 u 4 biex tikseb 92.

$$\frac{92a}{-1}$$

Kwalunkwe ħaġa diviża b '-1 jagħtik oppost tiegħu.

$$-92a$$