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Problemi Simili mit-Tiftix tal-Web

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\frac{\left(\sqrt{5}+\sqrt{3}\right)\left(\sqrt{5}+\sqrt{3}\right)}{\left(\sqrt{5}-\sqrt{3}\right)\left(\sqrt{5}+\sqrt{3}\right)}+\frac{\sqrt{5}-\sqrt{3}}{\sqrt{5}+\sqrt{3}}
Irrazzjonalizza d-denominatur tal-\frac{\sqrt{5}+\sqrt{3}}{\sqrt{5}-\sqrt{3}} billi timmultiplika in-numeratur u d-denominatur mill-\sqrt{5}+\sqrt{3}.
\frac{\left(\sqrt{5}+\sqrt{3}\right)\left(\sqrt{5}+\sqrt{3}\right)}{\left(\sqrt{5}\right)^{2}-\left(\sqrt{3}\right)^{2}}+\frac{\sqrt{5}-\sqrt{3}}{\sqrt{5}+\sqrt{3}}
Ikkunsidra li \left(\sqrt{5}-\sqrt{3}\right)\left(\sqrt{5}+\sqrt{3}\right). Il-multiplikazzjoni tista' tiġi ttrasformata fid-differenza tal-kwadrati li jużaw ir-regola: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{\left(\sqrt{5}+\sqrt{3}\right)\left(\sqrt{5}+\sqrt{3}\right)}{5-3}+\frac{\sqrt{5}-\sqrt{3}}{\sqrt{5}+\sqrt{3}}
Ikkwadra \sqrt{5}. Ikkwadra \sqrt{3}.
\frac{\left(\sqrt{5}+\sqrt{3}\right)\left(\sqrt{5}+\sqrt{3}\right)}{2}+\frac{\sqrt{5}-\sqrt{3}}{\sqrt{5}+\sqrt{3}}
Naqqas 3 minn 5 biex tikseb 2.
\frac{\left(\sqrt{5}+\sqrt{3}\right)^{2}}{2}+\frac{\sqrt{5}-\sqrt{3}}{\sqrt{5}+\sqrt{3}}
Immultiplika \sqrt{5}+\sqrt{3} u \sqrt{5}+\sqrt{3} biex tikseb \left(\sqrt{5}+\sqrt{3}\right)^{2}.
\frac{\left(\sqrt{5}\right)^{2}+2\sqrt{5}\sqrt{3}+\left(\sqrt{3}\right)^{2}}{2}+\frac{\sqrt{5}-\sqrt{3}}{\sqrt{5}+\sqrt{3}}
Uża teorema binomjali \left(a+b\right)^{2}=a^{2}+2ab+b^{2} biex tespandi \left(\sqrt{5}+\sqrt{3}\right)^{2}.
\frac{5+2\sqrt{5}\sqrt{3}+\left(\sqrt{3}\right)^{2}}{2}+\frac{\sqrt{5}-\sqrt{3}}{\sqrt{5}+\sqrt{3}}
Il-kwadrat ta' \sqrt{5} huwa 5.
\frac{5+2\sqrt{15}+\left(\sqrt{3}\right)^{2}}{2}+\frac{\sqrt{5}-\sqrt{3}}{\sqrt{5}+\sqrt{3}}
Biex timmultiplika \sqrt{5} u \sqrt{3}, immultiplika n-numri taħt l-għerq kwadrat.
\frac{5+2\sqrt{15}+3}{2}+\frac{\sqrt{5}-\sqrt{3}}{\sqrt{5}+\sqrt{3}}
Il-kwadrat ta' \sqrt{3} huwa 3.
\frac{8+2\sqrt{15}}{2}+\frac{\sqrt{5}-\sqrt{3}}{\sqrt{5}+\sqrt{3}}
Żid 5 u 3 biex tikseb 8.
4+\sqrt{15}+\frac{\sqrt{5}-\sqrt{3}}{\sqrt{5}+\sqrt{3}}
Iddividi kull terminu ta' 8+2\sqrt{15} b'2 biex tikseb4+\sqrt{15}.
4+\sqrt{15}+\frac{\left(\sqrt{5}-\sqrt{3}\right)\left(\sqrt{5}-\sqrt{3}\right)}{\left(\sqrt{5}+\sqrt{3}\right)\left(\sqrt{5}-\sqrt{3}\right)}
Irrazzjonalizza d-denominatur tal-\frac{\sqrt{5}-\sqrt{3}}{\sqrt{5}+\sqrt{3}} billi timmultiplika in-numeratur u d-denominatur mill-\sqrt{5}-\sqrt{3}.
4+\sqrt{15}+\frac{\left(\sqrt{5}-\sqrt{3}\right)\left(\sqrt{5}-\sqrt{3}\right)}{\left(\sqrt{5}\right)^{2}-\left(\sqrt{3}\right)^{2}}
Ikkunsidra li \left(\sqrt{5}+\sqrt{3}\right)\left(\sqrt{5}-\sqrt{3}\right). Il-multiplikazzjoni tista' tiġi ttrasformata fid-differenza tal-kwadrati li jużaw ir-regola: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
4+\sqrt{15}+\frac{\left(\sqrt{5}-\sqrt{3}\right)\left(\sqrt{5}-\sqrt{3}\right)}{5-3}
Ikkwadra \sqrt{5}. Ikkwadra \sqrt{3}.
4+\sqrt{15}+\frac{\left(\sqrt{5}-\sqrt{3}\right)\left(\sqrt{5}-\sqrt{3}\right)}{2}
Naqqas 3 minn 5 biex tikseb 2.
4+\sqrt{15}+\frac{\left(\sqrt{5}-\sqrt{3}\right)^{2}}{2}
Immultiplika \sqrt{5}-\sqrt{3} u \sqrt{5}-\sqrt{3} biex tikseb \left(\sqrt{5}-\sqrt{3}\right)^{2}.
4+\sqrt{15}+\frac{\left(\sqrt{5}\right)^{2}-2\sqrt{5}\sqrt{3}+\left(\sqrt{3}\right)^{2}}{2}
Uża teorema binomjali \left(a-b\right)^{2}=a^{2}-2ab+b^{2} biex tespandi \left(\sqrt{5}-\sqrt{3}\right)^{2}.
4+\sqrt{15}+\frac{5-2\sqrt{5}\sqrt{3}+\left(\sqrt{3}\right)^{2}}{2}
Il-kwadrat ta' \sqrt{5} huwa 5.
4+\sqrt{15}+\frac{5-2\sqrt{15}+\left(\sqrt{3}\right)^{2}}{2}
Biex timmultiplika \sqrt{5} u \sqrt{3}, immultiplika n-numri taħt l-għerq kwadrat.
4+\sqrt{15}+\frac{5-2\sqrt{15}+3}{2}
Il-kwadrat ta' \sqrt{3} huwa 3.
4+\sqrt{15}+\frac{8-2\sqrt{15}}{2}
Żid 5 u 3 biex tikseb 8.
4+\sqrt{15}+4-\sqrt{15}
Iddividi kull terminu ta' 8-2\sqrt{15} b'2 biex tikseb4-\sqrt{15}.
8+\sqrt{15}-\sqrt{15}
Żid 4 u 4 biex tikseb 8.
8
Ikkombina \sqrt{15} u -\sqrt{15} biex tikseb 0.