g(sinx)+log(cosx)+log2=0 सोडवा

$$g ( \sin x ) + \log ( \cos x ) + \log 2 = 0$$

g साठी सोडवा (जटिल उत्तर)

$$\left\{\begin{matrix}g=-\frac{\ln(\cos(x))+\ln(2)}{\ln(10)\sin(x)}\text{, }&\nexists n_{4}\in \mathrm{Z}\text{ : }x=\frac{\pi n_{4}}{2}\\g\in \mathrm{C}\text{, }&\exists n_{3}\in \mathrm{Z}\text{ : }\left(x=2\pi n_{3}+\frac{5\pi }{3}\text{ or }x=2\pi n_{3}+\frac{\pi }{3}\right)\text{ and }\nexists n_{1}\in \mathrm{Z}\text{ : }x=\pi n_{1}+\frac{\pi }{2}\text{ and }\exists n_{2}\in \mathrm{Z}\text{ : }x=\pi n_{2}\end{matrix}\right.$$

g साठी सोडवा

$$g=-\frac{\ln(\cos(x))+\ln(2)}{\ln(10)\sin(x)}$$

$$\nexists n_{2}\in \mathrm{Z}\text{ : }x=\pi n_{2}\text{ and }\exists n_{1}\in \mathrm{Z}\text{ : }\left(x>2\pi n_{1}-\frac{\pi }{2}\text{ and }x<2\pi n_{1}+\frac{\pi }{2}\right)$$