y^2=sin(log_{10}({1/x^2})) सोडवा

$${ y }^{ 2 } = \sin ( \log_{ 10 }({ \frac{ 1 }{ { x }^{ 2 } } }) )$$

y साठी सोडवा (जटिल उत्तर)

$$y=-\sqrt{\sin(\log(\frac{1}{x^{2}}))}$$

$$y=\sqrt{\sin(\log(\frac{1}{x^{2}}))}\text{, }x\neq 0$$

y साठी सोडवा

$$y=\sqrt{-\sin(\log(x^{2}))}$$

$$y=-\sqrt{-\sin(\log(x^{2}))}\text{, }\nexists n_{1}\in \mathrm{Z}\text{ : }\left(\left(x>100^{\frac{\pi n_{1}}{2}}\text{ and }x<10^{\pi n_{1}+\frac{\pi }{2}}\right)\text{ or }\left(x>-10^{\pi n_{1}+\frac{\pi }{2}}\text{ and }x<-100^{\frac{\pi n_{1}}{2}}\right)\right)\text{ and }x\neq 0$$