{l}{x^2+y^3=12}{x+2y=5} सोडवा

$$\left. \begin{array} { l } { x ^ { 2 } + y ^ { 3 } = 12 } \\ { x + 2 y = 5 } \end{array} \right.$$

x, y साठी सोडवा

$$x=\frac{-4\sqrt{19}\cos(\frac{\arccos(\frac{1199\sqrt{19}}{5776})}{3})-4\sqrt{57}\sin(\frac{\arccos(\frac{1199\sqrt{19}}{5776})}{3})+23}{3}\approx 0.446660138\text{, }y=\frac{2\left(\sqrt{19}\cos(\frac{\arccos(\frac{1199\sqrt{19}}{5776})}{3})+\sqrt{57}\sin(\frac{\arccos(\frac{1199\sqrt{19}}{5776})}{3})-2\right)}{3}\approx 2.276669931$$

$$x=\frac{8\sqrt{19}\cos(\frac{\arccos(\frac{1199\sqrt{19}}{5776})}{3})+23}{3}\approx 19.165710597\text{, }y=\frac{4\left(-\sqrt{19}\cos(\frac{\arccos(\frac{1199\sqrt{19}}{5776})}{3})-1\right)}{3}\approx -7.082855298$$

$$x=\frac{4\sqrt{57}\sin(\frac{\arccos(\frac{1199\sqrt{19}}{5776})}{3})-4\sqrt{19}\cos(\frac{\arccos(\frac{1199\sqrt{19}}{5776})}{3})+23}{3}\approx 3.387629265\text{, }y=\frac{2\left(\sqrt{19}\cos(\frac{\arccos(\frac{1199\sqrt{19}}{5776})}{3})-\sqrt{57}\sin(\frac{\arccos(\frac{1199\sqrt{19}}{5776})}{3})-2\right)}{3}\approx 0.806185368$$