{l}{text{A.}y=1/3sin(2x+pi/6)quadtext{B.}y=1/3sin(2x+pi/3)} सोडवा

$$\left. \begin{array} { l } { \text { A. } y = \frac { 1 } { 3 } \sin ( 2 x + \frac { \pi } { 6 } ) \quad \text { B. } y = \frac { 1 } { 3 } \sin ( 2 x + \frac { \pi } { 3 } ) } \end{array} \right.$$

y, x साठी सोडवा

$$x\in \cup n_{1},\frac{\pi n_{1}}{2}+\frac{\pi }{8}$$

$$n_{1}\in \mathrm{Z}$$

$$y\in \cup n_{1},\frac{\left(\sqrt{2}+\sqrt{6}\right)\left(-1\right)^{n_{1}}}{12}$$

$$n_{1}\in \mathrm{Z}$$