{l}{b=-x^3+5x^2-x}{y={(-x+5x-b/x)}}{z=y}{text{Solvefor}atext{where}}{a=z} सोडवा

$$\left. \begin{array} { l } { b = -x ^ {3} + 5 x ^ {2} - x }\\ { y = {(-x + 5 x - \frac{b}{x})} }\\ { z = y }\\ { \text{Solve for } a \text{ where} } \\ { a = z } \end{array} \right.$$

x, y, z साठी सोडवा

$$\left\{\begin{matrix}x=\frac{\sqrt{a^{2}+16b}+a}{8}\text{, }y=a\text{, }z=a\text{, }&b\geq -\frac{a^{2}}{16}\text{ and }\left(b\neq 0\text{ or }a>0\right)\text{ and }\left(\frac{\sqrt{a^{2}+16b}+a}{8}\right)^{3}-5\times \left(\frac{\sqrt{a^{2}+16b}+a}{8}\right)^{2}+\frac{\sqrt{a^{2}+16b}}{8}+b=-\frac{a}{8}\\x=\frac{-\sqrt{a^{2}+16b}+a}{8}\text{, }y=a\text{, }z=a\text{, }&b\geq -\frac{a^{2}}{16}\text{ and }b\neq 0\text{ and }\left(\frac{-\sqrt{a^{2}+16b}+a}{8}\right)^{3}-5\times \left(\frac{-\sqrt{a^{2}+16b}+a}{8}\right)^{2}-\frac{\sqrt{a^{2}+16b}}{8}+b=-\frac{a}{8}\end{matrix}\right.$$