{l}{a^2+4a+1=0}{b^2+4b+1=0} सोडवा

$$\left\{ \begin{array} { l } { a ^ { 2 } + 4 a + 1 = 0 } \\ { b ^ { 2 } + 4 b + 1 = 0 } \end{array} \right.$$

a, b साठी सोडवा (जटिल उत्तर)

$$a=-\left(\sqrt{3}+2\right)\approx -3.732050808\text{, }b=-\left(\sqrt{3}+2\right)\approx -3.732050808$$

$$a=\sqrt{3}-2\approx -0.267949192\text{, }b=-\left(\sqrt{3}+2\right)\approx -3.732050808$$

$$a=-\left(\sqrt{3}+2\right)\approx -3.732050808\text{, }b=\sqrt{3}-2\approx -0.267949192$$

$$a=\sqrt{3}-2\approx -0.267949192\text{, }b=\sqrt{3}-2\approx -0.267949192$$

a, b साठी सोडवा

$$a=-\sqrt{3}-2\approx -3.732050808\text{, }b=-\left(\sqrt{3}+2\right)\approx -3.732050808$$

$$a=\sqrt{3}-2\approx -0.267949192\text{, }b=-\left(\sqrt{3}+2\right)\approx -3.732050808$$

$$a=-\sqrt{3}-2\approx -3.732050808\text{, }b=\sqrt{3}-2\approx -0.267949192$$

$$a=\sqrt{3}-2\approx -0.267949192\text{, }b=\sqrt{3}-2\approx -0.267949192$$