Atrisiniet 11x=9x/5y+13y

$$11x= \frac{ 9x }{ 5y } +13y$$

Atrast x

$$x=\frac{65y^{2}}{55y-9}$$

$$y\neq \frac{9}{55}\text{ and }y\neq 0$$

Lineāra vienādojuma risināšanas darbības

Reiziniet vienādojuma abas puses ar 5y.

$$11x\times 5y=9x+13y\times 5y$$

Reiziniet 11 un 5, lai iegūtu 55.

$$55xy=9x+13y\times 5y$$

Reiziniet y un y, lai iegūtu y^{2}.

$$55xy=9x+13y^{2}\times 5$$

Reiziniet 13 un 5, lai iegūtu 65.

$$55xy=9x+65y^{2}$$

Atņemiet 9x no abām pusēm.

$$55xy-9x=65y^{2}$$

Savelciet visus locekļus, kuros ir x.

$$\left(55y-9\right)x=65y^{2}$$

Daliet abas puses ar 55y-9.

$$\frac{\left(55y-9\right)x}{55y-9}=\frac{65y^{2}}{55y-9}$$

Dalīšana ar 55y-9 atsauc reizināšanu ar 55y-9.

$$x=\frac{65y^{2}}{55y-9}$$

Atrast y (complex solution)

$$y=-\frac{\sqrt{3025x^{2}-2340x}}{130}+\frac{11x}{26}$$

$$y=\frac{\sqrt{3025x^{2}-2340x}}{130}+\frac{11x}{26}\text{, }x\neq 0$$

Atrast y

$$y=-\frac{\sqrt{3025x^{2}-2340x}}{130}+\frac{11x}{26}$$

$$y=\frac{\sqrt{3025x^{2}-2340x}}{130}+\frac{11x}{26}\text{, }x\geq \frac{468}{605}\text{ or }x<0$$