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\frac{33+2}{3}b^{2}+\frac{3\times 4+1}{4}b-\frac{6\times 6+5}{6}-\frac{2\times 2+1}{2}b^{2}+\frac{4\times 3+1}{3}b+\frac{1\times 12+11}{12}
Reiziniet 11 un 3, lai iegūtu 33.
\frac{35}{3}b^{2}+\frac{3\times 4+1}{4}b-\frac{6\times 6+5}{6}-\frac{2\times 2+1}{2}b^{2}+\frac{4\times 3+1}{3}b+\frac{1\times 12+11}{12}
Saskaitiet 33 un 2, lai iegūtu 35.
\frac{35}{3}b^{2}+\frac{12+1}{4}b-\frac{6\times 6+5}{6}-\frac{2\times 2+1}{2}b^{2}+\frac{4\times 3+1}{3}b+\frac{1\times 12+11}{12}
Reiziniet 3 un 4, lai iegūtu 12.
\frac{35}{3}b^{2}+\frac{13}{4}b-\frac{6\times 6+5}{6}-\frac{2\times 2+1}{2}b^{2}+\frac{4\times 3+1}{3}b+\frac{1\times 12+11}{12}
Saskaitiet 12 un 1, lai iegūtu 13.
\frac{35}{3}b^{2}+\frac{13}{4}b-\frac{36+5}{6}-\frac{2\times 2+1}{2}b^{2}+\frac{4\times 3+1}{3}b+\frac{1\times 12+11}{12}
Reiziniet 6 un 6, lai iegūtu 36.
\frac{35}{3}b^{2}+\frac{13}{4}b-\frac{41}{6}-\frac{2\times 2+1}{2}b^{2}+\frac{4\times 3+1}{3}b+\frac{1\times 12+11}{12}
Saskaitiet 36 un 5, lai iegūtu 41.
\frac{35}{3}b^{2}+\frac{13}{4}b-\frac{41}{6}-\frac{4+1}{2}b^{2}+\frac{4\times 3+1}{3}b+\frac{1\times 12+11}{12}
Reiziniet 2 un 2, lai iegūtu 4.
\frac{35}{3}b^{2}+\frac{13}{4}b-\frac{41}{6}-\frac{5}{2}b^{2}+\frac{4\times 3+1}{3}b+\frac{1\times 12+11}{12}
Saskaitiet 4 un 1, lai iegūtu 5.
\frac{55}{6}b^{2}+\frac{13}{4}b-\frac{41}{6}+\frac{4\times 3+1}{3}b+\frac{1\times 12+11}{12}
Savelciet \frac{35}{3}b^{2} un -\frac{5}{2}b^{2}, lai iegūtu \frac{55}{6}b^{2}.
\frac{55}{6}b^{2}+\frac{13}{4}b-\frac{41}{6}+\frac{12+1}{3}b+\frac{1\times 12+11}{12}
Reiziniet 4 un 3, lai iegūtu 12.
\frac{55}{6}b^{2}+\frac{13}{4}b-\frac{41}{6}+\frac{13}{3}b+\frac{1\times 12+11}{12}
Saskaitiet 12 un 1, lai iegūtu 13.
\frac{55}{6}b^{2}+\frac{91}{12}b-\frac{41}{6}+\frac{1\times 12+11}{12}
Savelciet \frac{13}{4}b un \frac{13}{3}b, lai iegūtu \frac{91}{12}b.
\frac{55}{6}b^{2}+\frac{91}{12}b-\frac{41}{6}+\frac{12+11}{12}
Reiziniet 1 un 12, lai iegūtu 12.
\frac{55}{6}b^{2}+\frac{91}{12}b-\frac{41}{6}+\frac{23}{12}
Saskaitiet 12 un 11, lai iegūtu 23.
\frac{55}{6}b^{2}+\frac{91}{12}b-\frac{59}{12}
Saskaitiet -\frac{41}{6} un \frac{23}{12}, lai iegūtu -\frac{59}{12}.
\frac{33+2}{3}b^{2}+\frac{3\times 4+1}{4}b-\frac{6\times 6+5}{6}-\frac{2\times 2+1}{2}b^{2}+\frac{4\times 3+1}{3}b+\frac{1\times 12+11}{12}
Reiziniet 11 un 3, lai iegūtu 33.
\frac{35}{3}b^{2}+\frac{3\times 4+1}{4}b-\frac{6\times 6+5}{6}-\frac{2\times 2+1}{2}b^{2}+\frac{4\times 3+1}{3}b+\frac{1\times 12+11}{12}
Saskaitiet 33 un 2, lai iegūtu 35.
\frac{35}{3}b^{2}+\frac{12+1}{4}b-\frac{6\times 6+5}{6}-\frac{2\times 2+1}{2}b^{2}+\frac{4\times 3+1}{3}b+\frac{1\times 12+11}{12}
Reiziniet 3 un 4, lai iegūtu 12.
\frac{35}{3}b^{2}+\frac{13}{4}b-\frac{6\times 6+5}{6}-\frac{2\times 2+1}{2}b^{2}+\frac{4\times 3+1}{3}b+\frac{1\times 12+11}{12}
Saskaitiet 12 un 1, lai iegūtu 13.
\frac{35}{3}b^{2}+\frac{13}{4}b-\frac{36+5}{6}-\frac{2\times 2+1}{2}b^{2}+\frac{4\times 3+1}{3}b+\frac{1\times 12+11}{12}
Reiziniet 6 un 6, lai iegūtu 36.
\frac{35}{3}b^{2}+\frac{13}{4}b-\frac{41}{6}-\frac{2\times 2+1}{2}b^{2}+\frac{4\times 3+1}{3}b+\frac{1\times 12+11}{12}
Saskaitiet 36 un 5, lai iegūtu 41.
\frac{35}{3}b^{2}+\frac{13}{4}b-\frac{41}{6}-\frac{4+1}{2}b^{2}+\frac{4\times 3+1}{3}b+\frac{1\times 12+11}{12}
Reiziniet 2 un 2, lai iegūtu 4.
\frac{35}{3}b^{2}+\frac{13}{4}b-\frac{41}{6}-\frac{5}{2}b^{2}+\frac{4\times 3+1}{3}b+\frac{1\times 12+11}{12}
Saskaitiet 4 un 1, lai iegūtu 5.
\frac{55}{6}b^{2}+\frac{13}{4}b-\frac{41}{6}+\frac{4\times 3+1}{3}b+\frac{1\times 12+11}{12}
Savelciet \frac{35}{3}b^{2} un -\frac{5}{2}b^{2}, lai iegūtu \frac{55}{6}b^{2}.
\frac{55}{6}b^{2}+\frac{13}{4}b-\frac{41}{6}+\frac{12+1}{3}b+\frac{1\times 12+11}{12}
Reiziniet 4 un 3, lai iegūtu 12.
\frac{55}{6}b^{2}+\frac{13}{4}b-\frac{41}{6}+\frac{13}{3}b+\frac{1\times 12+11}{12}
Saskaitiet 12 un 1, lai iegūtu 13.
\frac{55}{6}b^{2}+\frac{91}{12}b-\frac{41}{6}+\frac{1\times 12+11}{12}
Savelciet \frac{13}{4}b un \frac{13}{3}b, lai iegūtu \frac{91}{12}b.
\frac{55}{6}b^{2}+\frac{91}{12}b-\frac{41}{6}+\frac{12+11}{12}
Reiziniet 1 un 12, lai iegūtu 12.
\frac{55}{6}b^{2}+\frac{91}{12}b-\frac{41}{6}+\frac{23}{12}
Saskaitiet 12 un 11, lai iegūtu 23.
\frac{55}{6}b^{2}+\frac{91}{12}b-\frac{59}{12}
Saskaitiet -\frac{41}{6} un \frac{23}{12}, lai iegūtu -\frac{59}{12}.