Atrisiniet -a=sqrt{2a^2-3ab}

$$- a = \sqrt { 2 a ^ { 2 } - 3 a b }$$

Atrast b

$$\left\{\begin{matrix}b=\frac{a}{3}\text{, }&a\leq 0\\b\in \mathrm{R}\text{, }&a=0\end{matrix}\right,$$

Vienādojumu sakņu atrisināšanas darbības

Mainiet puses tā, lai visi mainīgie locekļi atrastos pa kreisi.

$$\sqrt{2a^{2}-3ab}=-a$$

Kāpiniet kvadrātā abas vienādojuma puses.

$$\left(-3a\right)b+2a^{2}=a^{2}$$

Atņemiet 2a^{2} no vienādojuma abām pusēm.

$$\left(-3a\right)b+2a^{2}-2a^{2}=a^{2}-2a^{2}$$

Atņemot 2a^{2} no sevis, paliek 0.

$$\left(-3a\right)b=a^{2}-2a^{2}$$

Atņemiet 2a^{2} no a^{2}.

$$\left(-3a\right)b=-a^{2}$$

Daliet abas puses ar -3a.

$$\frac{\left(-3a\right)b}{-3a}=-\frac{a^{2}}{-3a}$$

Dalīšana ar -3a atsauc reizināšanu ar -3a.

$$b=-\frac{a^{2}}{-3a}$$

Daliet -a^{2} ar -3a.

$$b=\frac{a}{3}$$

Atrast a (complex solution)

$$\left\{\begin{matrix}\\a=0\text{, }&\text{unconditionally}\\a=3b\text{, }&arg(b)\geq \pi \text{ or }b=0\end{matrix}\right,$$

Atrast b (complex solution)

$$\left\{\begin{matrix}b=\frac{a}{3}\text{, }&arg(a)\geq \pi \text{ or }a=0\\b\in \mathrm{C}\text{, }&a=0\end{matrix}\right,$$

Atrast a

$$\left\{\begin{matrix}\\a=0\text{, }&\text{unconditionally}\\a=3b\text{, }&b\leq 0\end{matrix}\right,$$