Atrast b (complex solution)
\left\{\begin{matrix}b=-i\ln(\frac{-2\cos(h)-\sqrt{2}\sqrt{\cos(2h)-7}}{4})+2\pi n_{1}\text{, }n_{1}\in \mathrm{Z}\text{, }&\frac{\sqrt{2}\left(\sqrt{2}\cos(h)+\sqrt{\cos(2h)-7}\right)}{4}\neq 0\\b=-i\ln(\frac{-2\cos(h)+\sqrt{2}\sqrt{\cos(2h)-7}}{4})+2\pi n_{2}\text{, }n_{2}\in \mathrm{Z}\text{, }&\frac{\sqrt{2}\left(\sqrt{2}\cos(h)-\sqrt{\cos(2h)-7}\right)}{4}\neq 0\end{matrix}\right,
Atrast h (complex solution)
\left\{\begin{matrix}h=-i\ln(-\left(2\cos(b)+\sqrt{2\cos(2b)+1}\right))+2\pi n_{1}\text{, }n_{1}\in \mathrm{Z}\text{, }&2\cos(b)+\sqrt{2\cos(2b)+1}\neq 0\\h=-i\ln(-\left(2\cos(b)-\sqrt{2\cos(2b)+1}\right))+2\pi n_{2}\text{, }n_{2}\in \mathrm{Z}\text{, }&2\cos(b)-\sqrt{2\cos(2b)+1}\neq 0\end{matrix}\right,
Atrast b
b=\arccos(\frac{\cos(h)}{2})+2\pi n_{1}-\pi \text{, }n_{1}\in \mathrm{Z}
b=-\arccos(\frac{\cos(h)}{2})+2\pi n_{2}+\pi \text{, }n_{2}\in \mathrm{Z}
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