Atrisiniet frac{4sqrt{3}}{2-sqrt{2}}-30/4sqrt{3-sqrt{18}}-frac{sqrt{18}}{3-sqrt{12}}

$$\frac { 4 \sqrt { 3 } } { 2 - \sqrt { 2 } } - \frac { 30 } { 4 \sqrt { 3 } - \sqrt { 18 } } - \frac { \sqrt { 18 } } { 3 - \sqrt { 12 } }$$

Izrēķināt

$$4\sqrt{6}\approx 9,797958971$$

Īsās risinājuma darbības

Atbrīvojieties no iracionalitātes saucēju ar \frac{4\sqrt{3}}{2-\sqrt{2}}, reizinot skaitītāju un saucēju ar 2+\sqrt{2}.

$$\frac{4\sqrt{3}\left(2+\sqrt{2}\right)}{\left(2-\sqrt{2}\right)\left(2+\sqrt{2}\right)}-\frac{30}{4\sqrt{3}-\sqrt{18}}-\frac{\sqrt{18}}{3-\sqrt{12}}$$

Apsveriet \left(2-\sqrt{2}\right)\left(2+\sqrt{2}\right). Reizināšanu var pārvērst par kvadrātu starpību, izmantojot šo kārtulu: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{4\sqrt{3}\left(2+\sqrt{2}\right)}{2^{2}-\left(\sqrt{2}\right)^{2}}-\frac{30}{4\sqrt{3}-\sqrt{18}}-\frac{\sqrt{18}}{3-\sqrt{12}}$$

Kāpiniet 2 kvadrātā. Kāpiniet \sqrt{2} kvadrātā.

$$\frac{4\sqrt{3}\left(2+\sqrt{2}\right)}{4-2}-\frac{30}{4\sqrt{3}-\sqrt{18}}-\frac{\sqrt{18}}{3-\sqrt{12}}$$

Atņemiet 2 no 4, lai iegūtu 2.

$$\frac{4\sqrt{3}\left(2+\sqrt{2}\right)}{2}-\frac{30}{4\sqrt{3}-\sqrt{18}}-\frac{\sqrt{18}}{3-\sqrt{12}}$$

Sadaliet reizinātājos 18=3^{2}\times 2. Pārrakstiet reizinājuma kvadrātsakni \sqrt{3^{2}\times 2} kā kvadrātveida saknes \sqrt{3^{2}}\sqrt{2}. Izvelciet kvadrātsakni no 3^{2}.

$$\frac{4\sqrt{3}\left(2+\sqrt{2}\right)}{2}-\frac{30}{4\sqrt{3}-3\sqrt{2}}-\frac{\sqrt{18}}{3-\sqrt{12}}$$

Atbrīvojieties no iracionalitātes saucēju ar \frac{30}{4\sqrt{3}-3\sqrt{2}}, reizinot skaitītāju un saucēju ar 4\sqrt{3}+3\sqrt{2}.

$$\frac{4\sqrt{3}\left(2+\sqrt{2}\right)}{2}-\frac{30\left(4\sqrt{3}+3\sqrt{2}\right)}{\left(4\sqrt{3}-3\sqrt{2}\right)\left(4\sqrt{3}+3\sqrt{2}\right)}-\frac{\sqrt{18}}{3-\sqrt{12}}$$

Apsveriet \left(4\sqrt{3}-3\sqrt{2}\right)\left(4\sqrt{3}+3\sqrt{2}\right). Reizināšanu var pārvērst par kvadrātu starpību, izmantojot šo kārtulu: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{4\sqrt{3}\left(2+\sqrt{2}\right)}{2}-\frac{30\left(4\sqrt{3}+3\sqrt{2}\right)}{\left(4\sqrt{3}\right)^{2}-\left(-3\sqrt{2}\right)^{2}}-\frac{\sqrt{18}}{3-\sqrt{12}}$$

Paplašiniet \left(4\sqrt{3}\right)^{2}.

$$\frac{4\sqrt{3}\left(2+\sqrt{2}\right)}{2}-\frac{30\left(4\sqrt{3}+3\sqrt{2}\right)}{4^{2}\left(\sqrt{3}\right)^{2}-\left(-3\sqrt{2}\right)^{2}}-\frac{\sqrt{18}}{3-\sqrt{12}}$$

Aprēķiniet 4 pakāpē 2 un iegūstiet 16.

$$\frac{4\sqrt{3}\left(2+\sqrt{2}\right)}{2}-\frac{30\left(4\sqrt{3}+3\sqrt{2}\right)}{16\left(\sqrt{3}\right)^{2}-\left(-3\sqrt{2}\right)^{2}}-\frac{\sqrt{18}}{3-\sqrt{12}}$$

Skaitļa \sqrt{3} kvadrāts ir 3.

$$\frac{4\sqrt{3}\left(2+\sqrt{2}\right)}{2}-\frac{30\left(4\sqrt{3}+3\sqrt{2}\right)}{16\times 3-\left(-3\sqrt{2}\right)^{2}}-\frac{\sqrt{18}}{3-\sqrt{12}}$$

Reiziniet 16 un 3, lai iegūtu 48.

$$\frac{4\sqrt{3}\left(2+\sqrt{2}\right)}{2}-\frac{30\left(4\sqrt{3}+3\sqrt{2}\right)}{48-\left(-3\sqrt{2}\right)^{2}}-\frac{\sqrt{18}}{3-\sqrt{12}}$$

Paplašiniet \left(-3\sqrt{2}\right)^{2}.

$$\frac{4\sqrt{3}\left(2+\sqrt{2}\right)}{2}-\frac{30\left(4\sqrt{3}+3\sqrt{2}\right)}{48-\left(-3\right)^{2}\left(\sqrt{2}\right)^{2}}-\frac{\sqrt{18}}{3-\sqrt{12}}$$

Aprēķiniet -3 pakāpē 2 un iegūstiet 9.

$$\frac{4\sqrt{3}\left(2+\sqrt{2}\right)}{2}-\frac{30\left(4\sqrt{3}+3\sqrt{2}\right)}{48-9\left(\sqrt{2}\right)^{2}}-\frac{\sqrt{18}}{3-\sqrt{12}}$$

Skaitļa \sqrt{2} kvadrāts ir 2.

$$\frac{4\sqrt{3}\left(2+\sqrt{2}\right)}{2}-\frac{30\left(4\sqrt{3}+3\sqrt{2}\right)}{48-9\times 2}-\frac{\sqrt{18}}{3-\sqrt{12}}$$

Reiziniet 9 un 2, lai iegūtu 18.

$$\frac{4\sqrt{3}\left(2+\sqrt{2}\right)}{2}-\frac{30\left(4\sqrt{3}+3\sqrt{2}\right)}{48-18}-\frac{\sqrt{18}}{3-\sqrt{12}}$$

Atņemiet 18 no 48, lai iegūtu 30.

$$\frac{4\sqrt{3}\left(2+\sqrt{2}\right)}{2}-\frac{30\left(4\sqrt{3}+3\sqrt{2}\right)}{30}-\frac{\sqrt{18}}{3-\sqrt{12}}$$

Saīsiniet 30 un 30.

$$\frac{4\sqrt{3}\left(2+\sqrt{2}\right)}{2}-\left(4\sqrt{3}+3\sqrt{2}\right)-\frac{\sqrt{18}}{3-\sqrt{12}}$$

Lai atrastu 4\sqrt{3}+3\sqrt{2} pretējo vērtību, atrodiet katra locekļa pretējo vērtību.

$$\frac{4\sqrt{3}\left(2+\sqrt{2}\right)}{2}-4\sqrt{3}-3\sqrt{2}-\frac{\sqrt{18}}{3-\sqrt{12}}$$

Sadaliet reizinātājos 18=3^{2}\times 2. Pārrakstiet reizinājuma kvadrātsakni \sqrt{3^{2}\times 2} kā kvadrātveida saknes \sqrt{3^{2}}\sqrt{2}. Izvelciet kvadrātsakni no 3^{2}.

$$\frac{4\sqrt{3}\left(2+\sqrt{2}\right)}{2}-4\sqrt{3}-3\sqrt{2}-\frac{3\sqrt{2}}{3-\sqrt{12}}$$

Sadaliet reizinātājos 12=2^{2}\times 3. Pārrakstiet reizinājuma kvadrātsakni \sqrt{2^{2}\times 3} kā kvadrātveida saknes \sqrt{2^{2}}\sqrt{3}. Izvelciet kvadrātsakni no 2^{2}.

$$\frac{4\sqrt{3}\left(2+\sqrt{2}\right)}{2}-4\sqrt{3}-3\sqrt{2}-\frac{3\sqrt{2}}{3-2\sqrt{3}}$$

Atbrīvojieties no iracionalitātes saucēju ar \frac{3\sqrt{2}}{3-2\sqrt{3}}, reizinot skaitītāju un saucēju ar 3+2\sqrt{3}.

$$\frac{4\sqrt{3}\left(2+\sqrt{2}\right)}{2}-4\sqrt{3}-3\sqrt{2}-\frac{3\sqrt{2}\left(3+2\sqrt{3}\right)}{\left(3-2\sqrt{3}\right)\left(3+2\sqrt{3}\right)}$$

Apsveriet \left(3-2\sqrt{3}\right)\left(3+2\sqrt{3}\right). Reizināšanu var pārvērst par kvadrātu starpību, izmantojot šo kārtulu: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{4\sqrt{3}\left(2+\sqrt{2}\right)}{2}-4\sqrt{3}-3\sqrt{2}-\frac{3\sqrt{2}\left(3+2\sqrt{3}\right)}{3^{2}-\left(-2\sqrt{3}\right)^{2}}$$

Aprēķiniet 3 pakāpē 2 un iegūstiet 9.

$$\frac{4\sqrt{3}\left(2+\sqrt{2}\right)}{2}-4\sqrt{3}-3\sqrt{2}-\frac{3\sqrt{2}\left(3+2\sqrt{3}\right)}{9-\left(-2\sqrt{3}\right)^{2}}$$

Paplašiniet \left(-2\sqrt{3}\right)^{2}.

$$\frac{4\sqrt{3}\left(2+\sqrt{2}\right)}{2}-4\sqrt{3}-3\sqrt{2}-\frac{3\sqrt{2}\left(3+2\sqrt{3}\right)}{9-\left(-2\right)^{2}\left(\sqrt{3}\right)^{2}}$$

Aprēķiniet -2 pakāpē 2 un iegūstiet 4.

$$\frac{4\sqrt{3}\left(2+\sqrt{2}\right)}{2}-4\sqrt{3}-3\sqrt{2}-\frac{3\sqrt{2}\left(3+2\sqrt{3}\right)}{9-4\left(\sqrt{3}\right)^{2}}$$

Skaitļa \sqrt{3} kvadrāts ir 3.

$$\frac{4\sqrt{3}\left(2+\sqrt{2}\right)}{2}-4\sqrt{3}-3\sqrt{2}-\frac{3\sqrt{2}\left(3+2\sqrt{3}\right)}{9-4\times 3}$$

Reiziniet 4 un 3, lai iegūtu 12.

$$\frac{4\sqrt{3}\left(2+\sqrt{2}\right)}{2}-4\sqrt{3}-3\sqrt{2}-\frac{3\sqrt{2}\left(3+2\sqrt{3}\right)}{9-12}$$

Atņemiet 12 no 9, lai iegūtu -3.

$$\frac{4\sqrt{3}\left(2+\sqrt{2}\right)}{2}-4\sqrt{3}-3\sqrt{2}-\frac{3\sqrt{2}\left(3+2\sqrt{3}\right)}{-3}$$

Saīsiniet -3 un -3.

$$\frac{4\sqrt{3}\left(2+\sqrt{2}\right)}{2}-4\sqrt{3}-3\sqrt{2}-\left(-\sqrt{2}\left(3+2\sqrt{3}\right)\right)$$

Skaitļa -\sqrt{2}\left(3+2\sqrt{3}\right) pretstats ir \sqrt{2}\left(3+2\sqrt{3}\right).

$$\frac{4\sqrt{3}\left(2+\sqrt{2}\right)}{2}-4\sqrt{3}-3\sqrt{2}+\sqrt{2}\left(3+2\sqrt{3}\right)$$

Lai saskaitītu vai atņemtu izteiksmes, izvērsiet tās, vienādojot saucējus. Reiziniet -4\sqrt{3}-3\sqrt{2} reiz \frac{2}{2}.

$$\frac{4\sqrt{3}\left(2+\sqrt{2}\right)}{2}+\frac{2\left(-4\sqrt{3}-3\sqrt{2}\right)}{2}+\sqrt{2}\left(3+2\sqrt{3}\right)$$

Tā kā \frac{4\sqrt{3}\left(2+\sqrt{2}\right)}{2} un \frac{2\left(-4\sqrt{3}-3\sqrt{2}\right)}{2} ir viens un tas pats saucējs, saskaitiet tos, saskaitot to skaitītājus.

$$\frac{4\sqrt{3}\left(2+\sqrt{2}\right)+2\left(-4\sqrt{3}-3\sqrt{2}\right)}{2}+\sqrt{2}\left(3+2\sqrt{3}\right)$$

Veiciet reizināšanas darbības izteiksmē 4\sqrt{3}\left(2+\sqrt{2}\right)+2\left(-4\sqrt{3}-3\sqrt{2}\right).

$$\frac{8\sqrt{3}+4\sqrt{6}-8\sqrt{3}-6\sqrt{2}}{2}+\sqrt{2}\left(3+2\sqrt{3}\right)$$

Veiciet aprēķinus izteiksmē 8\sqrt{3}+4\sqrt{6}-8\sqrt{3}-6\sqrt{2}.

$$\frac{4\sqrt{6}-6\sqrt{2}}{2}+\sqrt{2}\left(3+2\sqrt{3}\right)$$

Daliet katru 4\sqrt{6}-6\sqrt{2} locekli ar 2, lai iegūtu 2\sqrt{6}-3\sqrt{2}.

$$2\sqrt{6}-3\sqrt{2}+\sqrt{2}\left(3+2\sqrt{3}\right)$$

Izmantojiet distributīvo īpašību, lai reizinātu \sqrt{2} ar 3+2\sqrt{3}.

$$2\sqrt{6}-3\sqrt{2}+3\sqrt{2}+2\sqrt{2}\sqrt{3}$$

Lai reiziniet \sqrt{2} un \sqrt{3}, reiziniet numurus zem kvadrātveida saknes.

$$2\sqrt{6}-3\sqrt{2}+3\sqrt{2}+2\sqrt{6}$$

Savelciet -3\sqrt{2} un 3\sqrt{2}, lai iegūtu 0.

$$2\sqrt{6}+2\sqrt{6}$$

Savelciet 2\sqrt{6} un 2\sqrt{6}, lai iegūtu 4\sqrt{6}.

$$4\sqrt{6}$$