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\frac{\left(\frac{\left(\left(1-\frac{3}{8}+\frac{4}{5}-\frac{11}{20}\right)\left(\frac{3}{14}+\frac{5}{7}-1+\frac{3}{2}\right)\right)^{2}}{\left(-1+\frac{2}{4}\right)^{2}}\right)^{2}}{\left(\frac{5}{6}+\frac{1}{2}-\frac{1}{12}\right)^{2}}
Daliet 2 ar 2, lai iegūtu 1.
\frac{\left(\frac{\left(\left(\frac{5}{8}+\frac{4}{5}-\frac{11}{20}\right)\left(\frac{3}{14}+\frac{5}{7}-1+\frac{3}{2}\right)\right)^{2}}{\left(-1+\frac{2}{4}\right)^{2}}\right)^{2}}{\left(\frac{5}{6}+\frac{1}{2}-\frac{1}{12}\right)^{2}}
Atņemiet \frac{3}{8} no 1, lai iegūtu \frac{5}{8}.
\frac{\left(\frac{\left(\left(\frac{57}{40}-\frac{11}{20}\right)\left(\frac{3}{14}+\frac{5}{7}-1+\frac{3}{2}\right)\right)^{2}}{\left(-1+\frac{2}{4}\right)^{2}}\right)^{2}}{\left(\frac{5}{6}+\frac{1}{2}-\frac{1}{12}\right)^{2}}
Saskaitiet \frac{5}{8} un \frac{4}{5}, lai iegūtu \frac{57}{40}.
\frac{\left(\frac{\left(\frac{7}{8}\left(\frac{3}{14}+\frac{5}{7}-1+\frac{3}{2}\right)\right)^{2}}{\left(-1+\frac{2}{4}\right)^{2}}\right)^{2}}{\left(\frac{5}{6}+\frac{1}{2}-\frac{1}{12}\right)^{2}}
Atņemiet \frac{11}{20} no \frac{57}{40}, lai iegūtu \frac{7}{8}.
\frac{\left(\frac{\left(\frac{7}{8}\left(\frac{13}{14}-1+\frac{3}{2}\right)\right)^{2}}{\left(-1+\frac{2}{4}\right)^{2}}\right)^{2}}{\left(\frac{5}{6}+\frac{1}{2}-\frac{1}{12}\right)^{2}}
Saskaitiet \frac{3}{14} un \frac{5}{7}, lai iegūtu \frac{13}{14}.
\frac{\left(\frac{\left(\frac{7}{8}\left(-\frac{1}{14}+\frac{3}{2}\right)\right)^{2}}{\left(-1+\frac{2}{4}\right)^{2}}\right)^{2}}{\left(\frac{5}{6}+\frac{1}{2}-\frac{1}{12}\right)^{2}}
Atņemiet 1 no \frac{13}{14}, lai iegūtu -\frac{1}{14}.
\frac{\left(\frac{\left(\frac{7}{8}\times \frac{10}{7}\right)^{2}}{\left(-1+\frac{2}{4}\right)^{2}}\right)^{2}}{\left(\frac{5}{6}+\frac{1}{2}-\frac{1}{12}\right)^{2}}
Saskaitiet -\frac{1}{14} un \frac{3}{2}, lai iegūtu \frac{10}{7}.
\frac{\left(\frac{\left(\frac{5}{4}\right)^{2}}{\left(-1+\frac{2}{4}\right)^{2}}\right)^{2}}{\left(\frac{5}{6}+\frac{1}{2}-\frac{1}{12}\right)^{2}}
Reiziniet \frac{7}{8} un \frac{10}{7}, lai iegūtu \frac{5}{4}.
\frac{\left(\frac{\frac{25}{16}}{\left(-1+\frac{2}{4}\right)^{2}}\right)^{2}}{\left(\frac{5}{6}+\frac{1}{2}-\frac{1}{12}\right)^{2}}
Aprēķiniet \frac{5}{4} pakāpē 2 un iegūstiet \frac{25}{16}.
\frac{\left(\frac{\frac{25}{16}}{\left(-1+\frac{1}{2}\right)^{2}}\right)^{2}}{\left(\frac{5}{6}+\frac{1}{2}-\frac{1}{12}\right)^{2}}
Vienādot daļskaitli \frac{2}{4} līdz mazākajam loceklim, izvelkot un saīsinot 2.
\frac{\left(\frac{\frac{25}{16}}{\left(-\frac{1}{2}\right)^{2}}\right)^{2}}{\left(\frac{5}{6}+\frac{1}{2}-\frac{1}{12}\right)^{2}}
Saskaitiet -1 un \frac{1}{2}, lai iegūtu -\frac{1}{2}.
\frac{\left(\frac{\frac{25}{16}}{\frac{1}{4}}\right)^{2}}{\left(\frac{5}{6}+\frac{1}{2}-\frac{1}{12}\right)^{2}}
Aprēķiniet -\frac{1}{2} pakāpē 2 un iegūstiet \frac{1}{4}.
\frac{\left(\frac{25}{16}\times 4\right)^{2}}{\left(\frac{5}{6}+\frac{1}{2}-\frac{1}{12}\right)^{2}}
Daliet \frac{25}{16} ar \frac{1}{4}, reizinot \frac{25}{16} ar apgriezto daļskaitli \frac{1}{4} .
\frac{\left(\frac{25}{4}\right)^{2}}{\left(\frac{5}{6}+\frac{1}{2}-\frac{1}{12}\right)^{2}}
Reiziniet \frac{25}{16} un 4, lai iegūtu \frac{25}{4}.
\frac{\frac{625}{16}}{\left(\frac{5}{6}+\frac{1}{2}-\frac{1}{12}\right)^{2}}
Aprēķiniet \frac{25}{4} pakāpē 2 un iegūstiet \frac{625}{16}.
\frac{\frac{625}{16}}{\left(\frac{4}{3}-\frac{1}{12}\right)^{2}}
Saskaitiet \frac{5}{6} un \frac{1}{2}, lai iegūtu \frac{4}{3}.
\frac{\frac{625}{16}}{\left(\frac{5}{4}\right)^{2}}
Atņemiet \frac{1}{12} no \frac{4}{3}, lai iegūtu \frac{5}{4}.
\frac{\frac{625}{16}}{\frac{25}{16}}
Aprēķiniet \frac{5}{4} pakāpē 2 un iegūstiet \frac{25}{16}.
\frac{625}{16}\times \frac{16}{25}
Daliet \frac{625}{16} ar \frac{25}{16}, reizinot \frac{625}{16} ar apgriezto daļskaitli \frac{25}{16} .
25
Reiziniet \frac{625}{16} un \frac{16}{25}, lai iegūtu 25.