Atrisiniet [(a-1)(a-2)(a-3)-(a+1)(a+2)(a+3)]:(-4)

$$[ ( a - 1 ) ( a - 2 ) ( a - 3 ) - ( a + 1 ) ( a + 2 ) ( a + 3 ) ] : ( - 4 )$$

Izrēķināt

$$3\left(a^{2}+1\right)$$

Atrisinājuma darbības

Izmantojiet distributīvo īpašību, katru a-1 locekli reizinot ar katru a-2 locekli.

$$\frac{\left(a^{2}-2a-a+2\right)\left(a-3\right)-\left(a+1\right)\left(a+2\right)\left(a+3\right)}{-4}$$

Savelciet -2a un -a, lai iegūtu -3a.

$$\frac{\left(a^{2}-3a+2\right)\left(a-3\right)-\left(a+1\right)\left(a+2\right)\left(a+3\right)}{-4}$$

Izmantojiet distributīvo īpašību, katru a^{2}-3a+2 locekli reizinot ar katru a-3 locekli.

$$\frac{a^{3}-3a^{2}-3a^{2}+9a+2a-6-\left(a+1\right)\left(a+2\right)\left(a+3\right)}{-4}$$

Savelciet -3a^{2} un -3a^{2}, lai iegūtu -6a^{2}.

$$\frac{a^{3}-6a^{2}+9a+2a-6-\left(a+1\right)\left(a+2\right)\left(a+3\right)}{-4}$$

Savelciet 9a un 2a, lai iegūtu 11a.

$$\frac{a^{3}-6a^{2}+11a-6-\left(a+1\right)\left(a+2\right)\left(a+3\right)}{-4}$$

Izmantojiet distributīvo īpašību, katru a+1 locekli reizinot ar katru a+2 locekli.

$$\frac{a^{3}-6a^{2}+11a-6-\left(a^{2}+2a+a+2\right)\left(a+3\right)}{-4}$$

Savelciet 2a un a, lai iegūtu 3a.

$$\frac{a^{3}-6a^{2}+11a-6-\left(a^{2}+3a+2\right)\left(a+3\right)}{-4}$$

Izmantojiet distributīvo īpašību, katru a^{2}+3a+2 locekli reizinot ar katru a+3 locekli.

$$\frac{a^{3}-6a^{2}+11a-6-\left(a^{3}+3a^{2}+3a^{2}+9a+2a+6\right)}{-4}$$

Savelciet 3a^{2} un 3a^{2}, lai iegūtu 6a^{2}.

$$\frac{a^{3}-6a^{2}+11a-6-\left(a^{3}+6a^{2}+9a+2a+6\right)}{-4}$$

Savelciet 9a un 2a, lai iegūtu 11a.

$$\frac{a^{3}-6a^{2}+11a-6-\left(a^{3}+6a^{2}+11a+6\right)}{-4}$$

Lai atrastu a^{3}+6a^{2}+11a+6 pretējo vērtību, atrodiet katra locekļa pretējo vērtību.

$$\frac{a^{3}-6a^{2}+11a-6-a^{3}-6a^{2}-11a-6}{-4}$$

Savelciet a^{3} un -a^{3}, lai iegūtu 0.

$$\frac{-6a^{2}+11a-6-6a^{2}-11a-6}{-4}$$

Savelciet -6a^{2} un -6a^{2}, lai iegūtu -12a^{2}.

$$\frac{-12a^{2}+11a-6-11a-6}{-4}$$

Savelciet 11a un -11a, lai iegūtu 0.

$$\frac{-12a^{2}-6-6}{-4}$$

Atņemiet 6 no -6, lai iegūtu -12.

$$\frac{-12a^{2}-12}{-4}$$

Paplašināt

$$3a^{2}+3$$

Atrisinājuma darbības

Izmantojiet distributīvo īpašību, katru a-1 locekli reizinot ar katru a-2 locekli.

$$\frac{\left(a^{2}-2a-a+2\right)\left(a-3\right)-\left(a+1\right)\left(a+2\right)\left(a+3\right)}{-4}$$

Savelciet -2a un -a, lai iegūtu -3a.

$$\frac{\left(a^{2}-3a+2\right)\left(a-3\right)-\left(a+1\right)\left(a+2\right)\left(a+3\right)}{-4}$$

Izmantojiet distributīvo īpašību, katru a^{2}-3a+2 locekli reizinot ar katru a-3 locekli.

$$\frac{a^{3}-3a^{2}-3a^{2}+9a+2a-6-\left(a+1\right)\left(a+2\right)\left(a+3\right)}{-4}$$

Savelciet -3a^{2} un -3a^{2}, lai iegūtu -6a^{2}.

$$\frac{a^{3}-6a^{2}+9a+2a-6-\left(a+1\right)\left(a+2\right)\left(a+3\right)}{-4}$$

Savelciet 9a un 2a, lai iegūtu 11a.

$$\frac{a^{3}-6a^{2}+11a-6-\left(a+1\right)\left(a+2\right)\left(a+3\right)}{-4}$$

Izmantojiet distributīvo īpašību, katru a+1 locekli reizinot ar katru a+2 locekli.

$$\frac{a^{3}-6a^{2}+11a-6-\left(a^{2}+2a+a+2\right)\left(a+3\right)}{-4}$$

Savelciet 2a un a, lai iegūtu 3a.

$$\frac{a^{3}-6a^{2}+11a-6-\left(a^{2}+3a+2\right)\left(a+3\right)}{-4}$$

Izmantojiet distributīvo īpašību, katru a^{2}+3a+2 locekli reizinot ar katru a+3 locekli.

$$\frac{a^{3}-6a^{2}+11a-6-\left(a^{3}+3a^{2}+3a^{2}+9a+2a+6\right)}{-4}$$

Savelciet 3a^{2} un 3a^{2}, lai iegūtu 6a^{2}.

$$\frac{a^{3}-6a^{2}+11a-6-\left(a^{3}+6a^{2}+9a+2a+6\right)}{-4}$$

Savelciet 9a un 2a, lai iegūtu 11a.

$$\frac{a^{3}-6a^{2}+11a-6-\left(a^{3}+6a^{2}+11a+6\right)}{-4}$$

Lai atrastu a^{3}+6a^{2}+11a+6 pretējo vērtību, atrodiet katra locekļa pretējo vērtību.

$$\frac{a^{3}-6a^{2}+11a-6-a^{3}-6a^{2}-11a-6}{-4}$$

Savelciet a^{3} un -a^{3}, lai iegūtu 0.

$$\frac{-6a^{2}+11a-6-6a^{2}-11a-6}{-4}$$

Savelciet -6a^{2} un -6a^{2}, lai iegūtu -12a^{2}.

$$\frac{-12a^{2}+11a-6-11a-6}{-4}$$

Savelciet 11a un -11a, lai iegūtu 0.

$$\frac{-12a^{2}-6-6}{-4}$$

Atņemiet 6 no -6, lai iegūtu -12.

$$\frac{-12a^{2}-12}{-4}$$