Atrisiniet =368quad[(3/28a^2b)(-7/4ab)-(-1/8a^3b)(+2b)]:(-1/4a^2b^2)

$$= 368 \quad [ ( \frac { 3 } { 28 } a ^ { 2 } b ) ( - \frac { 7 } { 4 } a b ) - ( - \frac { 1 } { 8 } a ^ { 3 } b ) ( + 2 b ) ] : ( - \frac { 1 } { 4 } a ^ { 2 } b ^ { 2 } )$$

Izrēķināt

$$-92a$$

Atrisinājuma darbības

Lai reizinātu vienas bāzes pakāpes, saskaitiet kāpinātājus. Saskaitiet 2 un 1, lai iegūtu 3.

$$\frac{368\left(\frac{3}{28}a^{3}b\left(-\frac{7}{4}\right)b-\left(-\frac{1}{8}a^{3}b\times 2b\right)\right)}{-\frac{1}{4}a^{2}b^{2}}$$

Reiziniet b un b, lai iegūtu b^{2}.

$$\frac{368\left(\frac{3}{28}a^{3}b^{2}\left(-\frac{7}{4}\right)-\left(-\frac{1}{8}a^{3}b\times 2b\right)\right)}{-\frac{1}{4}a^{2}b^{2}}$$

Reiziniet b un b, lai iegūtu b^{2}.

$$\frac{368\left(\frac{3}{28}a^{3}b^{2}\left(-\frac{7}{4}\right)-\left(-\frac{1}{8}a^{3}b^{2}\times 2\right)\right)}{-\frac{1}{4}a^{2}b^{2}}$$

Reiziniet \frac{3}{28} un -\frac{7}{4}, lai iegūtu -\frac{3}{16}.

$$\frac{368\left(-\frac{3}{16}a^{3}b^{2}-\left(-\frac{1}{8}a^{3}b^{2}\times 2\right)\right)}{-\frac{1}{4}a^{2}b^{2}}$$

Reiziniet -\frac{1}{8} un 2, lai iegūtu -\frac{1}{4}.

$$\frac{368\left(-\frac{3}{16}a^{3}b^{2}-\left(-\frac{1}{4}a^{3}b^{2}\right)\right)}{-\frac{1}{4}a^{2}b^{2}}$$

Skaitļa -\frac{1}{4}a^{3}b^{2} pretstats ir \frac{1}{4}a^{3}b^{2}.

$$\frac{368\left(-\frac{3}{16}a^{3}b^{2}+\frac{1}{4}a^{3}b^{2}\right)}{-\frac{1}{4}a^{2}b^{2}}$$

Savelciet -\frac{3}{16}a^{3}b^{2} un \frac{1}{4}a^{3}b^{2}, lai iegūtu \frac{1}{16}a^{3}b^{2}.

$$\frac{368\times \frac{1}{16}a^{3}b^{2}}{-\frac{1}{4}a^{2}b^{2}}$$

Reiziniet 368 un \frac{1}{16}, lai iegūtu 23.

$$\frac{23a^{3}b^{2}}{-\frac{1}{4}a^{2}b^{2}}$$

Saīsiniet a^{2}b^{2} gan skaitītājā, gan saucējā.

$$\frac{23a}{-\frac{1}{4}}$$

Daliet 23a ar -\frac{1}{4}, reizinot 23a ar apgriezto daļskaitli -\frac{1}{4} .

$$\frac{23a\times 4}{-1}$$

Reiziniet 23 un 4, lai iegūtu 92.

$$\frac{92a}{-1}$$

Viss, ko dala ar-1, dod tā pretstatu.

$$-92a$$

Paplašināt

$$-92a$$

Atrisinājuma darbības

Lai reizinātu vienas bāzes pakāpes, saskaitiet kāpinātājus. Saskaitiet 2 un 1, lai iegūtu 3.

$$\frac{368\left(\frac{3}{28}a^{3}b\left(-\frac{7}{4}\right)b-\left(-\frac{1}{8}a^{3}b\times 2b\right)\right)}{-\frac{1}{4}a^{2}b^{2}}$$

Reiziniet b un b, lai iegūtu b^{2}.

$$\frac{368\left(\frac{3}{28}a^{3}b^{2}\left(-\frac{7}{4}\right)-\left(-\frac{1}{8}a^{3}b\times 2b\right)\right)}{-\frac{1}{4}a^{2}b^{2}}$$

Reiziniet b un b, lai iegūtu b^{2}.

$$\frac{368\left(\frac{3}{28}a^{3}b^{2}\left(-\frac{7}{4}\right)-\left(-\frac{1}{8}a^{3}b^{2}\times 2\right)\right)}{-\frac{1}{4}a^{2}b^{2}}$$

Reiziniet \frac{3}{28} un -\frac{7}{4}, lai iegūtu -\frac{3}{16}.

$$\frac{368\left(-\frac{3}{16}a^{3}b^{2}-\left(-\frac{1}{8}a^{3}b^{2}\times 2\right)\right)}{-\frac{1}{4}a^{2}b^{2}}$$

Reiziniet -\frac{1}{8} un 2, lai iegūtu -\frac{1}{4}.

$$\frac{368\left(-\frac{3}{16}a^{3}b^{2}-\left(-\frac{1}{4}a^{3}b^{2}\right)\right)}{-\frac{1}{4}a^{2}b^{2}}$$

Skaitļa -\frac{1}{4}a^{3}b^{2} pretstats ir \frac{1}{4}a^{3}b^{2}.

$$\frac{368\left(-\frac{3}{16}a^{3}b^{2}+\frac{1}{4}a^{3}b^{2}\right)}{-\frac{1}{4}a^{2}b^{2}}$$

Savelciet -\frac{3}{16}a^{3}b^{2} un \frac{1}{4}a^{3}b^{2}, lai iegūtu \frac{1}{16}a^{3}b^{2}.

$$\frac{368\times \frac{1}{16}a^{3}b^{2}}{-\frac{1}{4}a^{2}b^{2}}$$

Reiziniet 368 un \frac{1}{16}, lai iegūtu 23.

$$\frac{23a^{3}b^{2}}{-\frac{1}{4}a^{2}b^{2}}$$

Saīsiniet a^{2}b^{2} gan skaitītājā, gan saucējā.

$$\frac{23a}{-\frac{1}{4}}$$

Daliet 23a ar -\frac{1}{4}, reizinot 23a ar apgriezto daļskaitli -\frac{1}{4} .

$$\frac{23a\times 4}{-1}$$

Reiziniet 23 un 4, lai iegūtu 92.

$$\frac{92a}{-1}$$

Viss, ko dala ar-1, dod tā pretstatu.

$$-92a$$