सोडोवचें y=8-x+1/2(x-4)(2x-1/4x^2+1)-2(2-2x+1/4x^2-1)

$$y = 8 - x + \frac { 1 } { 2 } ( x - 4 ) ( 2 x - \frac { 1 } { 4 } x ^ { 2 } + 1 ) - 2 ( 2 - 2 x + \frac { 1 } { 4 } x ^ { 2 } - 1 )$$

y खातीर सोडोवचें

$$y=-\frac{\left(x-8\right)\left(x^{2}+4\right)}{8}$$

सोडोवणी पांवडे

x-4 न \frac{1}{2} गुणपाक विभाजक विशमाचो वापर करचो.

$$y=8-x+\left(\frac{1}{2}x-2\right)\left(2x-\frac{1}{4}x^{2}+1\right)-2\left(2-2x+\frac{1}{4}x^{2}-1\right)$$

वितरक गूणधर्माचो वापर करून \frac{1}{2}x-2 क 2x-\frac{1}{4}x^{2}+1 न गुणचें आनी संज्ञां भशेन एकठावणी करची.

$$y=8-x+\frac{3}{2}x^{2}-\frac{1}{8}x^{3}-\frac{7}{2}x-2-2\left(2-2x+\frac{1}{4}x^{2}-1\right)$$

-\frac{9}{2}x मेळोवंक -x आनी -\frac{7}{2}x एकठांय करचें.

$$y=8-\frac{9}{2}x+\frac{3}{2}x^{2}-\frac{1}{8}x^{3}-2-2\left(2-2x+\frac{1}{4}x^{2}-1\right)$$

6 मेळोवंक 8 आनी 2 वजा करचे.

$$y=6-\frac{9}{2}x+\frac{3}{2}x^{2}-\frac{1}{8}x^{3}-2\left(2-2x+\frac{1}{4}x^{2}-1\right)$$

1 मेळोवंक 2 आनी 1 वजा करचे.

$$y=6-\frac{9}{2}x+\frac{3}{2}x^{2}-\frac{1}{8}x^{3}-2\left(1-2x+\frac{1}{4}x^{2}\right)$$

1-2x+\frac{1}{4}x^{2} न -2 गुणपाक विभाजक विशमाचो वापर करचो.

$$y=6-\frac{9}{2}x+\frac{3}{2}x^{2}-\frac{1}{8}x^{3}-2+4x-\frac{1}{2}x^{2}$$

4 मेळोवंक 6 आनी 2 वजा करचे.

$$y=4-\frac{9}{2}x+\frac{3}{2}x^{2}-\frac{1}{8}x^{3}+4x-\frac{1}{2}x^{2}$$

-\frac{1}{2}x मेळोवंक -\frac{9}{2}x आनी 4x एकठांय करचें.

$$y=4-\frac{1}{2}x+\frac{3}{2}x^{2}-\frac{1}{8}x^{3}-\frac{1}{2}x^{2}$$

x^{2} मेळोवंक \frac{3}{2}x^{2} आनी -\frac{1}{2}x^{2} एकठांय करचें.

$$y=4-\frac{1}{2}x+x^{2}-\frac{1}{8}x^{3}$$