सोडोवचें y=sqrt{x}+9/sqrt{x}

$$y = \sqrt { x } + \frac { 9 } { \sqrt { x } }$$

x खातीर सोडोवचें (जटील सोल्यूशन)

$$\left\{\begin{matrix}x=\frac{\left(-\sqrt{y^{2}-36}+y\right)^{2}}{4}\text{, }&arg(\frac{-\sqrt{y^{2}-36}+y}{2})<\pi \\x=\frac{\left(\sqrt{y^{2}-36}+y\right)^{2}}{4}\text{, }&arg(\frac{\sqrt{y^{2}-36}+y}{2})<\pi \end{matrix}\right.$$

y खातीर सोडोवचें (जटील सोल्यूशन)

$$y=x^{-\frac{1}{2}}\left(x+9\right)$$

$$x\neq 0$$

x खातीर सोडोवचें

$$x=\frac{\left(-\sqrt{y^{2}-36}+y\right)^{2}}{4}$$

$$x=\frac{\left(\sqrt{y^{2}-36}+y\right)^{2}}{4}\text{, }y\geq 6$$

y खातीर सोडोवचें

$$y=\frac{x+9}{\sqrt{x}}$$

$$x>0$$