सोडोवचें y=sin4θ

$$y = \sin 4 \theta$$

θ खातीर सोडोवचें (जटील सोल्यूशन)

$$\theta =-\frac{i\ln(\sqrt{1-y^{2}}+iy)}{4}+\frac{\pi n_{1}}{2}\text{, }n_{1}\in \mathrm{Z}$$

$$\theta =-\frac{i\ln(-\sqrt{1-y^{2}}+iy)}{4}+\frac{\pi n_{2}}{2}\text{, }n_{2}\in \mathrm{Z}$$

y खातीर सोडोवचें

$$y=\sin(4\theta )$$

θ खातीर सोडोवचें

$$\theta =\frac{\arcsin(y)+2\pi n_{1}}{4}\text{, }n_{1}\in \mathrm{Z}$$

$$\theta =\frac{-\arcsin(y)+2\pi n_{2}+\pi }{4}\text{, }n_{2}\in \mathrm{Z}\text{, }|y|\leq 1$$