सोडोवचें xx+2x+1 | मायक्रोसॉफ्ट मॅथ सॉलवर

x x + 2 x + 1

गुणकपद

(x + 1)^{2}

सोडोवणी पांवडे

x x + 2 x + 1

समान संख्या गुणच्यो आनी एकठांय करच्यो.

x^{2} + 2 x + 1

गट करून गणीत फॅक्टर करचो. पयली, गणीत

x^{2} + a x + b x + 1

म्हूण परत बरोवपाची गरज आसता.

a

आनी

b

मेळोवंक, सोडोवंक यंत्रणां मांडची.

a + b = 2

a b = 1 \times 1 = 1

a b

सकारात्मक आसा देखून,

a

आनी

b

क एकूच खूण आसा.

a + b

सकारात्मक आसा देखून,

a

आनी

b

दोनूय सकारात्मक आसा. फकत तशें प्रणाली उत्तर आसा.

a = 1

b = 1

x^{2} + 2 x + 1

हें

(x^{2} + x) + (x + 1)

बरोवचें.

(x^{2} + x) + (x + 1)

फॅक्टर आवट

x

त

x^{2} + x

x (x + 1) + x + 1

फॅक्टर आवट सामान्य शब्द

x + 1

वितरीत गूणधर्म वापरून.

(x + 1) (x + 1)

बायनोमियल वर्गात परत बरोवप.

(x + 1)^{2}

मूल्यांकन करचें

(x + 1)^{2}

ग्राफ

प्रस्नमाची

Polynomial

x x + 2 x + 1

वॅब सोदांतल्यान समान समस्या

How do you multiply

(x + 2) (x + 10)

https://socratic.org/questions/how-do-you-multiply-x-2-x-10

(x + 2) (x + 10) = x^{2} + 12 x + 20

Explanation: If you find it helpful, you can use the FOIL mnemonic to help enumerate all the required ...

Factor each of the following into two polynomials of degree 1:

x, x + 2, x + 3

https://math.stackexchange.com/questions/2510891/factor-each-of-the-following-into-two-polynomials-of-degree-1-x-x2-x3

As you have computed, we obtain the condition

2 d + 3 b = 1

and

b d = 2

in the ring

Z / 6

. So we can take

b = 1

and

d = 2

(2 x + 1) (3 x + 2) = 6 x^{2} + 7 x + 2 = x + 2 .

How do you prove that the limit of

(1 - 5 x) = 16

as x approaches -3 using the epsilon delta proof?

https://socratic.org/questions/how-do-you-prove-that-the-limit-of-1-5x-16-as-x-approaches-3-using-the-epsilon-d

See proof below. Explanation: Given a positive

ϵ

, let

δ = \frac{ϵ}{5}

. Now for every

x

with

0 < ∣ x - (- 3) ∣ < δ

...

How do you use the distributive property to solve

2 (3 x + 6) = 9

https://socratic.org/questions/how-do-you-use-the-distributive-property-to-solve-2-3x-6-9

Multiply

2

times the term inside the parentheses. Then solve for

x

. Explanation:

2 (3 x + 6) = 9

Multiply

2

...

2 x + 1 = 13

https://www.tiger-algebra.com/drill/2x_1=13/

2x+1=13 One solution was found : x = 6 Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : ...

Why is

(1 + x)^{2}

less accurate than

(x + 2) x + 1

for small

x

https://math.stackexchange.com/questions/499159/why-is-1x2-less-accurate-than-x2x1-for-small-x

Let's us assume that

x \approx 1 0^{- (n - k)}

, where

n

is the number of significant digits remembered (in double arithmetic, this is roughly

16

) and

k

is a small positive integer. Now, compare:

1 + x

...

वांटचें

क्लिपबोर्डाचेर नक्कल केलां

x^{2}+2x+1

समान संख्या गुणच्यो आनी एकठांय करच्यो.

a+b=2 ab=1\times 1=1

गट करून गणीत फॅक्टर करचो. पयली, गणीत x^{2}+ax+bx+1 म्हूण परत बरोवपाची गरज आसता. a आनी b मेळोवंक, सोडोवंक यंत्रणां मांडची.

a=1 b=1

ab सकारात्मक आसा देखून, a आनी b क एकूच खूण आसा. a+b सकारात्मक आसा देखून, a आनी b दोनूय सकारात्मक आसा. फकत तशें प्रणाली उत्तर आसा.

\left(x^{2}+x\right)+\left(x+1\right)

x^{2}+2x+1 हें \left(x^{2}+x\right)+\left(x+1\right) बरोवचें.

x\left(x+1\right)+x+1

फॅक्टर आवट x त x^{2}+x.

\left(x+1\right)\left(x+1\right)

फॅक्टर आवट सामान्य शब्द x+1 वितरीत गूणधर्म वापरून.

\left(x+1\right)^{2}

बायनोमियल वर्गात परत बरोवप.

x^{2}+2x+1

x^{2} मेळोवंक x आनी x गुणचें.

देखीक

द्विघात समीकरण

x^{2} - 4 x - 5 = 0

त्रिकोणमिती

4 sin θ cos θ = 2 sin θ

रेखीय समीकरण

y = 3 x + 4

गणीत

699 * 533

मॅट्रिक्स

[2534] [2 - 1 0135]

समकालीन समीकरण

{8 x + 2 y = 46 7 x + 3 y = 47

भेदभाव

\frac{d}{d x} \frac{( 3 x ^{2} - 2 )}{( x - 5 )}

एकीकरण

\int_{0}^{1} x e^{- x^{2}} d x

मर्यादा

x \to - 3 lim \frac{x ^{2} - 9}{x ^{2} + 2 x - 3}

विशाय

विशाय

वॅब सोदांतल्यान समान समस्या

वांटचें

देखीक