सोडोवचें xdx-(5y^4+3)dy=0

$$x d x - ( 5 y ^ { 4 } + 3 ) d y = 0$$

d खातीर सोडोवचें (जटील सोल्यूशन)

$$\left\{\begin{matrix}\\d=0\text{, }&\text{unconditionally}\\d\in \mathrm{C}\text{, }&x=-\sqrt{5y^{5}+3y}\text{ or }x=\sqrt{5y^{5}+3y}\end{matrix}\right.$$

लिनियर समिकरण सोडोवंक पांवडे

x^{2} मेळोवंक x आनी x गुणचें.

$$x^{2}d-\left(5y^{4}+3\right)dy=0$$

d न 5y^{4}+3 गुणपाक विभाजक विशमाचो वापर करचो.

$$x^{2}d-\left(5y^{4}d+3d\right)y=0$$

y न 5y^{4}d+3d गुणपाक विभाजक विशमाचो वापर करचो.

$$x^{2}d-\left(5dy^{5}+3dy\right)=0$$

5dy^{5}+3dy चो विरोधी सोदूंक, दरेक सज्ञेचो विरोधी सोदचो.

$$x^{2}d-5dy^{5}-3dy=0$$

d आसपी सगळ्यो संज्ञा एकठांय करच्यो.

$$\left(x^{2}-5y^{5}-3y\right)d=0$$

x^{2}-5y^{5}-3y न0 क भाग लावचो.

$$d=0$$

d खातीर सोडोवचें

$$\left\{\begin{matrix}\\d=0\text{, }&\text{unconditionally}\\d\in \mathrm{R}\text{, }&y\geq 0\text{ and }|x|=\sqrt{y\left(5y^{4}+3\right)}\end{matrix}\right.$$

लिनियर समिकरण सोडोवंक पांवडे

x^{2} मेळोवंक x आनी x गुणचें.

$$x^{2}d-\left(5y^{4}+3\right)dy=0$$

d न 5y^{4}+3 गुणपाक विभाजक विशमाचो वापर करचो.

$$x^{2}d-\left(5y^{4}d+3d\right)y=0$$

y न 5y^{4}d+3d गुणपाक विभाजक विशमाचो वापर करचो.

$$x^{2}d-\left(5dy^{5}+3dy\right)=0$$

5dy^{5}+3dy चो विरोधी सोदूंक, दरेक सज्ञेचो विरोधी सोदचो.

$$x^{2}d-5dy^{5}-3dy=0$$

d आसपी सगळ्यो संज्ञा एकठांय करच्यो.

$$\left(x^{2}-5y^{5}-3y\right)d=0$$

x^{2}-5y^{5}-3y न0 क भाग लावचो.

$$d=0$$

x खातीर सोडोवचें (जटील सोल्यूशन)

$$\left\{\begin{matrix}\\x=-\sqrt{y\left(5y^{4}+3\right)}\text{; }x=\sqrt{y\left(5y^{4}+3\right)}\text{, }&\text{unconditionally}\\x\in \mathrm{C}\text{, }&d=0\end{matrix}\right.$$

x खातीर सोडोवचें

$$\left\{\begin{matrix}x=\sqrt{y\left(5y^{4}+3\right)}\text{; }x=-\sqrt{y\left(5y^{4}+3\right)}\text{, }&y\geq 0\\x\in \mathrm{R}\text{, }&d=0\end{matrix}\right.$$