सोडोवचें x^2geq12^21

$$x ^ { 2 } \geq 12 ^ { 21 }$$

x खातीर सोडोवचें

$$x\in (-\infty,-123834728448\sqrt{3}]\cup [123834728448\sqrt{3},\infty)$$

सोडोवणी पांवडे

46005119909369701466112 मेळोवंक 21 चो 12 पॉवर मेजचो.

$$x^{2}\geq 46005119909369701466112$$

46005119909369701466112 चें वर्गमूळ मेजचें आनी 123834728448\sqrt{3} मेळोवचें. 46005119909369701466112 हें \left(123834728448\sqrt{3}\right)^{2} बरोवचें.

$$x^{2}\geq \left(123834728448\sqrt{3}\right)^{2}$$

असमानताय |x|\geq 123834728448\sqrt{3} खातीर धरता.

$$|x|\geq 123834728448\sqrt{3}$$

|x|\geq 123834728448\sqrt{3} हें x\leq -123834728448\sqrt{3}\text{; }x\geq 123834728448\sqrt{3} बरोवचें.

$$x\leq -123834728448\sqrt{3}\text{; }x\geq 123834728448\sqrt{3}$$